6. Use the data from the questions above to complete the chi-square analysistable below.e(o-e)(o-e)²(o-e)2e7. Calculate the chi-square statistic: x².x²=Σ (o-e)²=e 5. Now assume that homozygous recessive individuals never survive. Youobserve that over the next 5 generations, the genotypic frequencies in thepopulation are:# of aa individuals # of Aa individuals # of AA individualsGeneration 150041585Generation 2250250500Generation 362188750Generation 447173780Generation 543157800

Let's understand the Chi-square formula before filling the table:χ2 = ∑ ((o - e)2/ e)Where:o :…

Answered: 6. Use the data from the questions…

Biology: The Unity and Diversity of Life (MindTap Course List)

14th Edition

ISBN:9781305073951

Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Chapter13: Observing Patterns In Inherited Traits

Section: Chapter Questions

Problem 4GP

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2. The following questions refer to the pedigree chart in the figure for a family, some of whose members exhibit the dominant trait, W. Affected individuals are indicated by a dark square or circle. 2 I ww Ww 2 34 5 6 III IV 1 23 A. What is the genotype of individual II-4? B. What is the genotype of individual II-5? C. If individual II-2 and his partner have a second child, what is the probability that their second child will be a normal, unaffected male? Show your work: 3. Phenylketonuria is an inherited disease caused by a recessive autosomal allele. If a woman and her husband are both carriers, what is the probability that their first child will be a phenotypically normal female? First, draw the pedigree for this family. Then, calculate the probability (show your work): 3 4. A man who is heterozygous for PTC tasting marries a woman who is homozygous recessive. They have two children. Their oldest daughter is a taster, and their youngest boy is a non-taster. What is the probability…
22.
Some recessive alleles have such a detrimental effect that they are lethal when present in both chromosomes of a pair. Homozygous recessives cannot survive and die at some point during embryonic development. Suppose that the allele r is lethal in the homozygous rr condition. What genotypic ratios would you expect among the living offspring of the following crosses? a. RRRr b. RrRr
2. Describe the phenotype of the cats with these genotypes (If allele not specified, assume wild type): CC ss OO BB dd McMc tt ww Light brown male with choco [Choose ] Light brown male with chocolate tips ctct ss OY bb TAt A uniformly colored black cat Light grey female with dark grey mackerel stripes Black female with large white patches Dark grey with black mackerel stripes Cc SS Oo BB TATA Cream male with small white patches and orange mackerel stripes CC Ss oY bb dd tt [Choose ]
Times New... - 14 BIU 1 .|. 2 Go To next Page 2. P1 = YY = yellow rose P2 = BB = blue rose Use a Punnett square to cross the P1 and P2 generation. What will be the probability of genotype and phenotype for the offspring. This trait exhibits Incomplete Dominance. Genotype: % YY % BB % YB Phenotype: % Yellow Rose % Blue Rose % Green Rose edu gear
4. In humans, cystic fibrosis and albinism are both inherited as independently assorting autosomal recessive traits. Use fto represent the recessive allele for cystic fibrosis and Ffor the allele for the unaffected condition. Use A to represent the dominant allele for normal melanin man is albino and heterozygous for cystic fibrosis. His wife has the unaffected phenotype for both traits, although her father had cystic fibrosis and a for the recessive allele for albinism. and her mother is albino. 4a. What is the genotype of the wife? 4b. What is the probability that a child of this couple is albino and has cystic fibrosis?
问题13 Achondroplasia (dwarfism) is an example of a dominantly inherited disease. Individuals who have the dominant gene (A) have the dwarfism phenotype, while normal height is recessive (a). What is the probability of having children with achondroplasia between a normal height female and a heterozygote achondroplasia male? 100% 75% 25% 50%
16.
Match the following letter representations with their genetic term. Heterozygous dominant 1. ww Homozygous recessive 2. Ww Gamete 3. ww 4. W Homozygous dominant
6. In a population of interest, 1 in 4000 women are affected with haemophilia A, an X-linked recessive condition. Assuming this population is mating randomly and available treatments mean haemophilia does not affect individual fitness. a) What is the carrier frequency in this population for Haemophilia A? b) What is the expected frequency of men affected with Haemophilia A?
1. What percentage of the offspring will have a homozygous recessive genotype? Gray fur White fur 2. What will be the ratio of gray fur to white fur in the offspring? 33 x 89 3. What percentage of the offspring will have a tall phenotype? Tall Short 4. What percentage of the offspring will have a homozygous recessive genotype? TT tt White eyes Dark eyes have white eyes? 5. What percentage of the offspring will 6. What percentage of the offspring will have a heterozygous genotype? PR PUO pp pa × Long beak Short beak 7. What percentage of the offspring will have a homozygous dominant genotype? 11 8. What will be the ratio of long beaks to Tutorial Sche
1. How many different types of gametes can be produced by an individual with the genotype Yy Ww Pp ee Bb? 2. If an individual with the genotype Yy Ww Pp ee Bb is crossed with another individual with the same genotype, what proportion of offspring will be homozygous recessive at all genes? 3. If an individual with genotype Yy Ww Pp ee Bb is crossed with an individual with the same genotype, what proportion of offspring will have the dominant phenotype for the four heterozygous loci?

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