If the frequency of allele A (p) is: p = 98 / 134 ≈ 0.731 and the frequency of allele B (q) is: q = [(6 * 2) + 24] / (67 * 2) = 36 / 134 ≈ 0.269, how do I calculate the sum of frequencies of all alleles?

If the frequency of allele A (p) is: p = 98 / 134 ≈ 0.731 and the frequency of allele B (q) is: q = [(6 * 2) + 24] / (67 * 2) = 36 / 134 ≈ 0.269, how do I calculate the sum of frequencies of all alleles?

Name: If the frequency of allele A (p) is: p = 98 / 134 ≈ 0.731 and the freq
Uploaded: 2024-03-20T06:43:04.000Z
Channel: Bartleby
Description: If the frequency of allele A (p) is: p = 98 / 134 ≈ 0.731 and the frequency of allele B (q) is: q = [(6 * 2) + 24] / (67 * 2) = 36 / 134 ≈ 0.269, how do I calculate the sum of frequencies of all alleles?

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter19: Population Genetics And Human Evolution

Section: Chapter Questions

Problem 9QP: Using the HardyWeinberg Law in Human Genetics Suppose you are monitoring the allelic and genotypic...

See similar textbooks

Similar questions

While studying the frequency of sickle-cell disease ("sickle cell anemia") in a population living in sub-Saharan Africa, you obtain the following data from a sample of n= 100 people (note that I chose a simpler system for identifying the alleles rather than using "Hb S" for sickle cell allele), which is the actual name and what you used in lab). What is the frequency of the sickle cell allele (b) in the sample below from a human population? Sample Data BB-60 individuals (No sickle cell disease) Bb-30 individuals (No sickle cell disease) bb-10 individuals (Sickle cell disease) 1. 0.25 2. 0.10 3. 0.35 4. 0.60 5. 0.20
There are two types of alleles: Type B1 and Type B2 (In total there are 10) Type B1 has 6 Type B2 has 4 Question: What is the probability of an individual in the offspring generation being homozygous [p^2] for B1? What is the probability of an individual in the offspring generation being homozygous [q^2] for B2? What is the probability of an individual in the offspring gen being heterozygous[2pq]?
Given the following pedigree (note that C7C, M4C, N2X, H6C, G9X, J1C, B8X, and P2X are the names of animals):
What does P-value indicate? In statistical analysis the results for two sets of data are presented with P < 0.01 and P<0.005. What does it mean?
Using the HardyWeinberg Law in Human Genetics Suppose you are monitoring the allelic and genotypic frequencies of the MN blood group locus (see Question 2 for a description of the MN blood group) in a small human population. You find that for 1-year-old children, the genotypic frequencies are MM = 0.25, MN = 0.5, and NN = 0.25, whereas the genotypic frequencies for adults are MM = 0.3, MN = 0.4, and NN = 0.3. a. Compute the M and N allele frequencies for 1-year-olds and adults. b. Are the allele frequencies in equilibrium in this population? c. Are the genotypic frequencies in equilibrium?
Recall that the alleles for blood groups are A, B, O, and that A and B are each dominant to O, and A and B are codominant (AA and AO= A blood type; BB and BO = B blood type; AB = AB blood type; OO = O blood type). According to the Red Cross, in the US Asian population the alleles frequencies of A, B, an O are 18.8%, 17.6%, and 63.6%, respectively. If a mother and son from this population have blood type AB and the father has blood type B, what is the probability that the father’s genotype is BB?
In a population of 200 people, an allele F has a frequency of 84%. What is the frequency of allele f? Using the Hardy-Weinberg equation, estimate the numbers of homozygous dominant, heterozygous, and homozygous recessive genotypes. (Remember that the formula is: p2 + 2pq + q2 = 1, where p represents the dominant allele and q represents the recessive allele.) *Be sure to account for all 200 people in the population.
Consider a Hardy-Weinburg Equilibrium population with an autosomal locus of 2 alleles, A1 and A2. If P(A1A2) = 8 * P(A1A1), what are the allele frequencies at the locus?
Below is a table of allele frequencies. Locus 1 Freq(116) = 0.3 Freq(120) = 0.4 Freq(124) = 0.3 Locus 2 Freq(88) = 0.6 Freq(92) = 0.4 Locus 3 Freq(180) = 0.1 Freq(183) = 0.5 Freq(186) = 0.4 You find a sample that has the following genotype: Locus 1: 116/124 Locus 2: 88/92 Locus 3: 186/186 What is the probability of getting a match to this sample by random chance? (Round your answer to 3 significant digits.)
"he equation p + 2pq + q° = 1 representing the lardy-Weinberg proportions examines genes with nly two alleles in a population. . Derive a similar equation describing the equilib- rium proportions of genotypes for a gene with three alleles. [Hint: Remember that the Hardy- Weinberg equation can be written as the binomial expansion (p + q)*.] A single gene with three alleles (r^, 1", and i) is responsible for the ABO blood groups. Individuals with blood type A can be either rr or ^ i; those with blood type B can be either 1" 1 or 1" i; people with AB blood are A ", and type O individuals are ii. Among Armenians, the frequency of is 0.360, the frequency of " is 0.104, and the frequency of i
The equation p + 2pq + q = 1 representing the Hardy-Weinberg proportions examines genes with only two alleles in a population. a. Derive a similar equation describing the equilib- rium proportions of genotypes for a gene with three alleles. [Hint: Remember that the Hardy- Weinberg equation can be written as the binomial expansion (p + q)*.] b. A single gene with three alleles (r, 1", and i) is responsible for the ABO blood groups. Individuals with blood type A can be either A or ^ i; those with blood type B can be either /* 1 or * i; people with AB blood are r*, and type O individuals are ii. Among Armenians, the frequency of ^ is 0.360, the frequency of 1 is 0.104, and the frequency of i is 0.536. Calculate the frequencies of individuals in this population with the four possible blood types, assuming Hardy-Weinberg equilibrium. %3D
What does the likelihood ratio mean?