Solutions for Bundle: Chemistry for Engineering Students, 3rd, Loose-Leaf + OWLv2 with QuickPrep 24-Months Printed Access Card
Problem 6CO:
• use standard reduction potentials to predict the spontaneous direction of a redox reaction.Problem 7CO:
• calculate the amount of metal plated, the amount of current needed, or the time required for an...Problem 13.5PAE:
For the following oxidationreduction reactions, identify the half-reactions and label them as...Problem 13.8PAE:
Which half-reaction takes place at the anode of an electrochemical cell? Which half-reaction takes...Problem 13.9PAE:
If a salt bridge contains KNO3 as its electrolyte, which ions diffuse into solution in the anode...Problem 13.10PAE:
If a salt bridge contains KNO3 as its electrolyte, which ions diffuse into solution in the cathode...Problem 13.11PAE:
The following oxidationreduction reactions are used in electrochemical cells. Write them using cell...Problem 13.12PAE:
Write a balanced chemical equation for the overall reaction in each of the following galvanic cells....Problem 13.13PAE:
For the reactions in parts (a) and (b) in the preceding problem, no anions at all are shown in the...Problem 13.14PAE:
Explain why the terms cell potential and electromotive force mean the same thing in electrochemical...Problem 13.15PAE:
How does galvanic corrosion differ from uniform corrosion of iron?Problem 13.17PAE:
A student who has mercury amalgam fillings in some of her teeth is eating a piece of candy. She...Problem 13.18PAE:
Based on the cell potential measured for the cells Co(s)|Co2+(aq) Cu 2+( aq)|Cu(...Problem 13.20PAE:
Four voltaic cells are set up. In each, one half-cell contains a standard hydrogen electrode. The...Problem 13.22PAE:
Explain why a large negative value for the standard reduction potential indicates a half-cell that...Problem 13.23PAE:
In tables of standard reduction potentials that start from large positive values at the top and...Problem 13.24PAE:
In the table of standard reduction potentials, locate the half-reactions for the reductions of the...Problem 13.25PAE:
Using values from the table of standard reduction potentials, calculate the cell potentials of the...Problem 13.26PAE:
Using values from the table of standard reduction potentials, calculate the cell potentials of the...Problem 13.27PAE:
One half-cell in a voltaic cell is constructed from a copper wire dipped into a 4.8103 M solution of...Problem 13.28PAE:
Four metals, A, B, C, and D, exhibit the following properties. (i) Only A and C react with 1.0 M...Problem 13.29PAE:
Use the Nernst equation to calculate the cell potentials of the following cells at 298 K. (a)...Problem 13.30PAE:
One half-cell in a voltaic cell is constructed from a silver wire dipped into a AgNO3 solution of...Problem 13.31PAE:
We noted that a tin-plated steel can corrodes more quickly than an unplated steel can. In cases of...Problem 13.32PAE:
The following half-cells are available: Ag(s);...Problem 13.35PAE:
In May 2000, a concrete pedestrian walkway collapsed in North Carolina, injuring more than 100...Problem 13.39PAE:
Calculate the standard free energy change for the following reactions using the standard cell...Problem 13.40PAE:
Suppose that you cannot find a table of standard reduction potentials. You remember that the...Problem 13.42PAE:
Which of the following reactions is (are) spontaneous at standard conditions? (a)...Problem 13.43PAE:
Consult a table of standard reduction potentials and determine which of the following reactions are...Problem 13.44PAE:
The equilibrium constant for a reaction is 31015 (a) Without carrying out any calculation, discuss...Problem 13.45PAE:
Some calculators cannot display results of an antilog calculation if the power of 10 is greater than...Problem 13.46PAE:
Calculate the equilibrium constant for the following reactions using data from the standard...Problem 13.47PAE:
Use the standard reduction potentials for the reactions: AgCl(s)+eAg(s)+Cl-(aq) and Ag+(aq)+eAg(s)...Problem 13.48PAE:
Hydrogen peroxide is often stored in the refrigerator to help keep it from decomposing according to...Problem 13.49PAE:
Calculate the equilibrium constant for the redox reactions that could occur in the following...Problem 13.51PAE:
An engineer is assigned to design an electrochemical cell that will deliver a potential of exactly...Problem 13.52PAE:
A magnesium bar with a mass of 6.0 kg is attached to a buried iron pipe to serve as a sacrificial...Problem 13.58PAE:
If you put a 9-volt battery in a smoke detector in your home or apartment, you are not installing a...Problem 13.59PAE:
If alkaline batteries were not alkaline but rather acidic (as in the older dry cell batteries), what...Problem 13.60PAE:
What would happen to the voltage of an alkaline battery if the zinc were replaced by steel? Assume...Problem 13.61PAE:
Battery manufacturers often assess batteries in terms of their specific energy (or energy capacity)....Problem 13.63PAE:
What product forms from the lead components of a lead storage battery? Why does mechanical shock...Problem 13.66PAE:
Assume the specifications of a Ni-Cd voltaic cell include delivery of 0.25 A of current for 1.00 h....Problem 13.68PAE:
What is the difference between active and passive electrolysis? Based on the common meanings of the...Problem 13.73PAE:
In an electroplating operation, the cell potential is sometimes 0 V. Why is a zero potential...Problem 13.77PAE:
Use the Internet to find electroplating companies that carry out silver plating. Popular impressions...Problem 13.79PAE:
If a current of 15 A is run through an electrolysis cell for 2.0 hours, how many moles of electrons...Problem 13.80PAE:
Suppose somebody in a laboratory doesn't quite turn off the current in an electrolysis cell so that...Problem 13.81PAE:
If a barrel plating run uses 200.0 A for exactly 6 hours for an electroplating application at 0.30...Problem 13.82PAE:
An electrical engineer is analyzing an electroplating run and wants to calculate the charge that has...Problem 13.83PAE:
In a copper plating experiment in which copper metal is deposited from a copper(ll) ion solution,...Problem 13.84PAE:
A metallurgist wants to gold-plate a thin sheet with the following dimensions: 1.5in8.5in0.0012in ....Problem 13.85PAE:
Tin-plated steel is used for "tin" cans. Suppose that in the production of sheets of tin-plated...Problem 13.86PAE:
An electrolysis cell for aluminum production operates at 5.0 V and a current of 1.0105 A. Calculate...Problem 13.87PAE:
If a plating line that deposits nickel (from NiCl2 solutions) operates at a voltage of 0.40 V with a...Problem 13.90PAE:
A small part with a surface area of 2.62 cm2 is plated with a gold coating that is 5.00104 mm thick....Problem 13.91PAE:
An engineer is designing a mirror for an optical system. A piece of metal that measures 1.3 cm by...Problem 13.94PAE:
What characteristic of lithium ions makes it practical to build a semipermeable separator that...Problem 13.95PAE:
Looking at Figure 13.23, describe how the operation of a lithium-ion battery does not lead to a...Problem 13.97PAE:
For a voltage-sensitive application, you are working on a battery that must have a working voltage...Problem 13.102PAE:
13.104 (a) What happens when a current is passed through a solution of dilute sulfuric acid to carry...Problem 13.103PAE:
A current is passed through a solution of copper(II) sulfate long enough to deposit 14.5 g of...Browse All Chapters of This Textbook
Chapter 1 - Introduction To ChemistryChapter 2 - Atoms And MoleculesChapter 3 - Molecules, Moles, And Chemical EquationsChapter 4 - StoichiometryChapter 5 - GasesChapter 6 - The Periodic Table And Atomic StructureChapter 7 - Chemical Bonding And Molecular StructureChapter 8 - Molecules And MaterialsChapter 9 - Energy And ChemistryChapter 10 - Entropy And The Second Law Of Thermodynamics
Sample Solutions for this Textbook
We offer sample solutions for Bundle: Chemistry for Engineering Students, 3rd, Loose-Leaf + OWLv2 with QuickPrep 24-Months Printed Access Card homework problems. See examples below:
The increase in application of the aluminum is due to its properties such as strength,...Chapter 1, Problem 1.46PAEChapter 1, Problem 1.47PAEChapter 1, Problem 1.59PAEChapter 1, Problem 1.89PAEChapter 2, Problem 1CODue to isotopes of an element we cannot define atomic mass of the element. Each isotope is present...Place the ion in proper manner cation first then anion. Formation of cation from calcium atom:...Chapter 2, Problem 2.19PAE
In the periodic table, elements increase in metallic nature when approaching the “left” side of the...Chapter 3, Problem 1COChapter 3, Problem 3.16PAEChapter 3, Problem 3.34PAEChapter 3, Problem 3.35PAEChapter 3, Problem 3.43PAEChapter 3, Problem 3.64PAEChapter 3, Problem 3.65PAEChapter 3, Problem 3.66PAEMolarity is defined as the number of moles of solute in 1 L of solution. The final solution is 0.45...Chapter 3, Problem 3.98PAEChapter 4, Problem 1COChapter 4, Problem 4.7PAEChapter 4, Problem 4.10PAEChapter 4, Problem 4.14PAEChapter 4, Problem 4.15PAEChapter 4, Problem 4.26PAEChapter 4, Problem 4.31PAEChapter 4, Problem 4.49PAEChapter 4, Problem 4.72PAEGiven information: Total mass of Alloy = 7.264 g Total mass of H2(g) released out = 0.3284 g...Chapter 4, Problem 4.87PAEReactions given below take place to result the given products....The physical properties of gases are as follows: The gases have no fixed shape and volume. The...Chapter 5, Problem 5.33PAEChapter 5, Problem 5.43PAEChapter 5, Problem 5.47PAEChapter 5, Problem 5.65PAENo of moles of gas =mass of gas molar mass of CH4 =15.0 g16.0 g/m ( mass of CH4( given)=15.0 g)molar...The ideal gas equation is as follows: PV=nRT Or, PV=(mM) RT Or, M=mRT/PV =( 2.298 g)( 0.0821 atm...Chapter 5, Problem 5.89PAEThus, total number of moles = [0.40+0.50+0.30] mol = 1.20 mol = N1 As given total pressure = P = 740...Step 1: Write the chemical equation The SO2 and O2 react to produce SO3 according to the equation: 2...Chapter 5, Problem 5.103PAEChapter 6, Problem 1COChapter 6, Problem 16COPauli’s exclusion principle and Hund’s rule are useful in writing electronic configurations of atoms...Chapter 6, Problem 6.17PAEλ=( hCE)h=6.634×10−34JsC=3×108m/sE=6.0×10−19J Putting these values in above equation you get λ=(...Chapter 6, Problem 6.42PAEAtomic radius is the distance between center of nucleus and outermost electron shell. Atomic radius...Chapter 6, Problem 6.85PAEChapter 6, Problem 6.86PAEChapter 7, Problem 1COChapter 7, Problem 7.72PAEThe electronic configuration of I is [Kr]4d105s25p5. In the excited state, the configuration becomes...The electronic configuration of P is 3s23p33d0. In the excited state, the configuration becomes...The electronic configuration of Xeis 4d105s25p65d0. In the excited state, the configuration becomes...Chapter 7, Problem 7.76PAEIn the structure of diamond each carbon atom is linked to four other carbon atoms forming a three...1 metric ton of silicon = 106 gm of silicon. On conversion of 106 gm of silicon to moles of silicon,...1 metric ton of silicon = 106 gm of silicon. On conversion of 106 gm of silicon to moles of silicon,...Chapter 9, Problem 1COChapter 9, Problem 9.15PAEChapter 9, Problem 9.16PAEChapter 9, Problem 9.37PAEChapter 9, Problem 9.48PAEChapter 9, Problem 9.52PAEChapter 9, Problem 9.55PAEChapter 9, Problem 9.58PAEChapter 9, Problem 9.79PAEChapter 9, Problem 9.85PAEThe given reaction is: 3CO2(g)+Si3N4(s)→2SiO2(s)+2N2(g)+3C(s) Reaction enthalpy can be calculated...1 barrel of oil can produce 19.5 gallons = 73815.5 mL of gasoline We know, 1 gallon = 3785.41 mL...The causes to obstacles in the recovery and recycling of plastic solid waste in terms of economic,...Based on the thermodynamics third law, ’At absolute zero of temperature, the entropy of every...Chapter 10, Problem 10.47PAEChapter 10, Problem 10.69PAEThe change in Gibbs free energy of a reaction is calculated as follows: ΔG0 = sum of ΔG0 (product) -...Chapter 10, Problem 10.75PAEChapter 10, Problem 10.76PAEChapter 10, Problem 10.84PAEChapter 10, Problem 10.88PAEChapter 10, Problem 10.91PAEChapter 10, Problem 10.101PAEChapter 10, Problem 10.102PAEOzone also formed at ground level but the mechanism and kinetics are very different from that in...Chapter 11, Problem 11.6PAEChapter 11, Problem 11.20PAEChapter 11, Problem 11.24PAEChapter 11, Problem 11.30PAEChapter 11, Problem 11.33PAEChapter 11, Problem 11.35PAEChapter 11, Problem 11.36PAEChapter 11, Problem 11.49PAEGiven Information: The table containing the total pressures in the reaction vessel during the...Chapter 11, Problem 11.57PAEO(g)+N2(g)→NO(g)+ N(g) The rate of the equation for the reaction can be written as follows. R= −k...Chapter 11, Problem 11.70PAE(a) The molar ratio of the reactant molecules, products in balance equation is called stoichiometry....Chapter 12, Problem 1COUsing the formula K = [C]eqc[D]eqd[A]eqa[B]eqb we can calculate the values of equilibrium constants...Chapter 12, Problem 12.36PAEWhen the salt is dissolved in water, it forms the ions. When AgBr is dissolved in water, it...Let solubility of ZnCO3 is 3 then ZnCO 3 ( S ) Zn2+(aq)M C O 3 2− ( aq )M Initial concentration...AgCN(S)⇌Ag+(aq)+CN−(aq)KSP=[Ag+][CN−] Solubility of AgCN is 7.73×10−9M, it means that Concentration...Chapter 12, Problem 12.65PAEChapter 12, Problem 12.67PAECH3COOH(aq)+H2O(l)→CH3COO−(aq)+H3O+(aq) Rate of equilibrium expression...NH3(g)+H2O(l)→NH4+(aq)+OH−(aq) Apply the concept aA+bB⇌cC+dD Rate of equilibrium reaction...The given reaction is as follows:H2(g)+Cl2(g)⇌2HCl(g) First step is to calculate the value of...Here, sulfur dioxide, sodium chloride and water are formed when sodium hydrogen sulfite is reacted...For reaction S(s)+O2(g)⇌SO2(g) Enthalpy change (ΔH0)=ΔHf0[Product]−ΔHf0[Reactants]...There are different types of corrosion: Pitting corrosion: is the most destructive type of...Chapter 13, Problem 3COCell potential in standard condition: Measurement of standard electrode potential of Zn2+/Zn...Chapter 13, Problem 13.26PAEChapter 13, Problem 13.29PAEChapter 13, Problem 13.32PAEIn this reaction, Half-cell reaction at the anode Ga(s)→Ga3+(aq)+3e− Half-cell reaction at the...Chapter 13, Problem 13.39PAEChapter 13, Problem 13.43PAEChapter 13, Problem 13.49PAEChapter 13, Problem 13.104PAEUse the given data to calculate the following: 1st Step: Calculate the total amount of charge...Cosmic rays are divided into mainly three types: galactic cosmic rays, extragalactic cosmic rays and...Because this is an alpha decay, the helium nucleus is ejected with decrease in mass number by 4 and...Atomic numbers of thorium and radium are 90 and 88, respectively. Consider the transformation:...The 232Th radioactive series beginning with 232Th and ending with 208Pb. The sequence occurs as...Given information: The experimentally determined mass of 14C is 14.003242 u. Formula used: E =...Given information: Experimentally determined mass of 7Li is 7.016004 u. Formula used: E = (Δm)c2Δm =...Given information: Experimentally determined mass of 14N is 14.003074 u. Formula used: E = (Δm)c2...Formula used: E = (Δm)c2Δm = Mass defectc = Velocity of light Calculation: Let’s calculate the...92235U+01n→52137Te+4097Zr+201n Apply Einstein’s equation E=Δmc2 Δm= Mass of product − mass of...Write the balanced nuclear reaction. 92235U+01n→3890Sr+54143NP+301n Mass of reactant =mu+mn (putting...The total amount of electrical energy generated by all the nuclear reactors is...Calculating decay constant for A26l as follows: k=0.693t 1 2 k=0.6937.17× 105 yr=9.66×10−7 yr−1 Now,...
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