4.80 The reaction shown below is used to destroy Freon-12 (CF 2 Cl 2 ), preventing its release into the atmosphere. What mass of NaF will be formed if 250.0 kg of CF 2 Cl 2 and 400.0 kg of Na 2 C 2 O 4 are heated and allowed to react to completion? CF 2 Cl 2 + 2 Na 2 C 2 O 4 → 2 NaF + 2 NaCl + C + 4CO 2
4.80 The reaction shown below is used to destroy Freon-12 (CF 2 Cl 2 ), preventing its release into the atmosphere. What mass of NaF will be formed if 250.0 kg of CF 2 Cl 2 and 400.0 kg of Na 2 C 2 O 4 are heated and allowed to react to completion? CF 2 Cl 2 + 2 Na 2 C 2 O 4 → 2 NaF + 2 NaCl + C + 4CO 2
4.80 The reaction shown below is used to destroy Freon-12 (CF2Cl2), preventing its release into the atmosphere. What mass of NaF will be formed if 250.0 kg of CF2Cl2 and 400.0 kg of Na2C2O4 are heated and allowed to react to completion?
CF
2
Cl
2
+
2 Na
2
C
2
O
4
→
2 NaF
+
2 NaCl
+
C
+
4CO
2
Expert Solution & Answer
Interpretation Introduction
Interpretation:
To calculate the mass of sodium fluoride required for the process.
Concept introduction:
Use the stoichiometric ratios in order to verify the total amount of moles
Use molar masses to calculate mass and moles.
Answer to Problem 4.72PAE
Solution:
125.31kg
Given:
m=250.0kgofCF2Cl2m=400.0kgofNa2C2O4
Explanation of Solution
Use stoichiometry to relate the amounts of moles of CF2Cl2 and phosphoric acid. Then use molar masses to calculate the mass of each material.
Verify the limiting reactant, and base the final calculation of sodium fluoride with the given species.
H2O2(aq) +3 I¯(aq) +2 H+(aq) → 13(aq) +2 H₂O(l)·
•••
Experiment [H2 O2]o (M)
[I]o (M) [H+]。 (M)
Initial rate (M/s)
1
0.15
0.15
0.05
0.00012
234
0.15
0.3
0.05
0.00024
0.3
0.15
0.05
0.00024
0.15
0.15
0.1
0.00048
Calculate the overall order of this reaction using the table data.
The U. S. Environmental Protection Agency (EPA) sets
limits on healthful levels of air pollutants. The
maximum level that the EPA considers safe for lead air
pollution is 1.5 μg/m³
Part A
If your lungs were filled with air containing this level of lead, how many lead atoms would be in your lungs? (Assume a total lung
volume of 5.40 L.)
ΜΕ ΑΣΦ
= 2.35 1013
?
atoms
! Check your rounding. Your final answer should be rounded to 2 significant figures in the last step.
No credit lost. Try again.
Y= - 0.039 (14.01) + 0.7949
Chapter 4 Solutions
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