Chapter SH, Problem 3.11MPS

To determine

To calculate:To find themaximum length with which a garden can be made if width of the garden is $8\frac{7}{8}$$feet$ and the fencing material is $40\frac{1}{2}$$feet$ long.

Answer to Problem 3.11MPS

Maximum length of the garden that can be made is $31\frac{5}{8}$$feet$ .

Explanation of Solution

Given information:

Width of the garden $=$$8\frac{7}{8}$$feet$

Fencing material $=$$40\frac{1}{2}$$feet$ long.

Calculation:

Given :

Width of the garden $=$$8\frac{7}{8}$$feet$

Width of the garden $=$$\frac{71}{8}$$feet$

Length of fencing material $=$$40\frac{1}{2}$$feet$

Length of fencing material $=$$\frac{81}{2}$$feet$

Maximum length of the garden that can be made $=$ Length of fencing material $-$ Width of the garden

Maximum length of the garden that can be made $=$$\frac{81}{2}-\frac{71}{8}$

Maximum length of the garden that can be made $=$$\frac{253}{8}$

Thus, the maximum length of the garden that can be madeis $31\frac{5}{8}$$feet$ .

Conclusion:

Maximum length of the garden that can be made is $31\frac{5}{8}$$feet$ .