Chapter SH, Problem 8.3.7EP

To determine

To calculate: To find the four solution of equation and write the solution in ordered pair

Answer to Problem 8.3.7EP

Solutions of equation are $\left(0,-3\right),\left(1,-\frac{5}{2}\right),\left(2,-2\right),\left(3,-\frac{3}{2}\right)$

Explanation of Solution

Given information:Equation is $y=\frac{1}{2}x-3$

Calculation:

Equation is given as

  $y=\frac{1}{2}x-3$

When $x=0$

  $\begin{array}{l}y=\frac{1}{2}\left(0\right)-3\\ y=0-3\\ y=-3\end{array}$

When $x=1$

  $\begin{array}{l}y=\frac{1}{2}\left(1\right)-3\\ y=\frac{1}{2}-3\\ y=\frac{1-6}{2}\\ y=-\frac{5}{2}\end{array}$

When $x=2$

  $\begin{array}{l}y=\frac{1}{2}\left(2\right)-3\\ y=\frac{2}{2}-3\\ y=1-3\\ y=-2\end{array}$

When $x=3$

  $\begin{array}{l}y=\frac{1}{2}\left(3\right)-3\\ y=\frac{3}{2}-3\\ y=\frac{3-6}{2}\\ y=-\frac{3}{2}\end{array}$

Solution of the equation are $\left(0,-3\right),\left(1,-\frac{5}{2}\right),\left(2,-2\right),\left(3,-\frac{3}{2}\right)$

Conclusion:

Hence, solutions of equation are $\left(0,-3\right),\left(1,-\frac{5}{2}\right),\left(2,-2\right),\left(3,-\frac{3}{2}\right)$