Chapter SH, Problem 13.6.10EP

To determine

To find:the probability $P(\text{ neither green nor yellow })$

Answer to Problem 13.6.10EP

The required probability is $\frac{2}{3}\text{ or }66.7\%$

Explanation of Solution

Given:

Number of blue marbles is 4

Number of red marbles is 6

Number of green marbles is 3

Number of yellow marbles is 2

Select one marble at random.

Calculation:

Total number of marbles is $4+6+3+2=15$

Number of non-green and non-yellow marbles is 10 .

  $\begin{array}{l}P(\text{ neither green nor yellow })=\frac{\text{ number of non-green, non-yellow marbles }}{\text{ total number of marbles }}\\ =\frac{10}{15}\\ =\frac{2}{3}\\ =66.7\%\end{array}$

Hence, the required probability is $\frac{2}{3}\text{ or }66.7\%$

Conclusion:

Therefore, the required probability is $\frac{2}{3}\text{ or }66.7\%$