Chapter SH, Problem 10.4.2EP

To determine

The length of hypotenuse in right angled triangle and round to nearest tenth, if needed.

  

Answer to Problem 10.4.2EP

The length of hypotenuse of the right angled triangle is $10in$ .

Explanation of Solution

Given:

  

Triangle with two sides are given.

Concept Used:

The Pythagoras theorem of right angled triangle is used.

The three sides of a any right angled triangle are associated with the Pythagoras theorem which is given by $c^2=a^2+b^2$

  $a,b$ are the sides of right angled triangle and $c$ is the hypotenuse.

Calculation:

For a given triangle,

  

Consider the sides of right angled triangle as $a,b,c$ in which $a,b$ are the sides of right angled triangle and $c$ is the hypotenuse in $in$ .

Hence,

  $\begin{array}{l}a=6in\\ b=8in\end{array}$

Now by using the Pythagoras Theorem find the value of hypotenuse side $c$ .

  $c^2=a^2+b^2$

Substitute the values in the above formula,

  $c^2=6^2+8^2$

  $=36+64$

  $c^2=100$

By taking square root on both the sides,

  $\sqrt{c^2}=\sqrt{100}$

  $c=10$

Conclusion:

Hence, length of hypotenuse of the right angled triangle is $10in$ .