Concept explainers
(a)
Interpretation:
Ion that is likely to be formed from iodine has to be given.
Concept Introduction:
Atoms of the element are neutral. They tend to lose or gain electrons in order to attain the stable octet configuration of the noble gas. Generally metals loses electrons and nonmetals gains electrons. Elements that are present in Group 1 to Group 13 tend to lose electrons until the noble-gas configuration of the noble gas present in previous period is attained. Elements that is present in Group 14 to Group 17 gain electron till the valence shell has the noble-gas electronic configuration. Metallic elements form cations while nonmetallic elements form anions.
Charge of the anion formed from main group element can be calculated by finding
(b)
Interpretation:
Ion that is likely to be formed from aluminium has to be given.
Concept Introduction:
Refer part (a).

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Chapter F Solutions
CHEMICAL PRINCIPLES (LL) W/ACCESS
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- b. H3C CH3 H3O+ ✓ H OHarrow_forward2. Provide reagents/conditions to accomplish the following syntheses. More than one step is required in some cases. a. CH3arrow_forwardIdentify and provide an explanation that distinguishes a qualitative and quantitative chemical analysis. Provide examples.arrow_forward
- Identify and provide an explanation of the operational principles behind a Atomic Absorption Spectrometer (AAS). List the steps involved.arrow_forwardInstructions: Complete the questions in the space provided. Show all your work 1. You are trying to determine the rate law expression for a reaction that you are completing at 25°C. You measure the initial reaction rate and the starting concentrations of the reactions for 4 trials. BrO³¯ (aq) + 5Br¯ (aq) + 6H* (aq) → 3Br₂ (l) + 3H2O (l) Initial rate Trial [BrO3] [H*] [Br] (mol/L) (mol/L) | (mol/L) (mol/L.s) 1 0.10 0.10 0.10 8.0 2 0.20 0.10 0.10 16 3 0.10 0.20 0.10 16 4 0.10 0.10 0.20 32 a. Based on the above data what is the rate law expression? b. Solve for the value of k (make sure to include proper units) 2. The proposed reaction mechanism is as follows: i. ii. BrО¸¯ (aq) + H+ (aq) → HBrO3 (aq) HBrO³ (aq) + H* (aq) → H₂BrO3* (aq) iii. H₂BrO³* (aq) + Br¯ (aq) → Br₂O₂ (aq) + H2O (l) [Fast] [Medium] [Slow] iv. Br₂O₂ (aq) + 4H*(aq) + 4Br(aq) → 3Br₂ (l) + H2O (l) [Fast] Evaluate the validity of this proposed reaction. Justify your answer.arrow_forwardе. Д CH3 D*, D20arrow_forward
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