Explanation Volume of I 3 − ( a q ) is given as 24.4 mL . Concentration of I 3 − ( a q ) is given as 0.0010 M . The number of moles of I 3 − is calculated using the equation shown below: n = V × c Substitute the values in the above equation: n = 24.4 mL × 0.0010 mol ⋅ L − 1 = 24.4 mL × 0.0010 mol ⋅ L − 1 × 1 L 1000 mL = 2.44 × 10 − 5 mol Thus, the number of moles of I 3 − ( a q ) ions is 2.44 × 10 − 5 mol . The balanced equation is given as follows: 6 Cu 2 + ( a q ) + 15 I − ( a q ) → 6 CuI ( a q ) + 3 I 3 − ( a q ) From the above equation it is found that six moles of Cu 2 + ( a q ) produces three moles of I 3 − ( a q ) . Thus, the total number of moles of Cu 2 + ( a q ) that produces 2.44 × 10 − 5 mol is calculated as follows: Number of moles of Cu 2 + = 2.44 × 10 − 5 mol I 3 − × 6 mol Cu 2 + 3 mol I 3 − = 4

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Author: ATKINS

Publisher: MAC HIGHER

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Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can b…

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Chapter F, Problem L.25E

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Mass percentage of copper in the super conductor has to be calculated.

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Chapter F, Problem L.24E

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Mass percentage of copper in the super conductor has to be calculated.

Solution Summary: The author calculates the mass percentage of copper in the super conductor using the equation shown below.

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Interpretation: Mass percentage of copper in the super conductor has to be calculated.

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Chapter F Solutions

Interpretation:

Mass percentage of copper in the super conductor has to be calculated.