Explanation Coulomb potential energy equation can be given as shown below; E p = Q 1 Q 2 4 π ε 0 r If the particles are separated by an infinite distance, then the potential energy is equal to zero. E p = Q 1 Q 2 4 π ε 0 r = 0 ( ∵ r = ∞ ) The distance between the electron and proton is 53 pm on moving it from infinity. Therefore, the energy possessed is calculated as shown below; E p = − ( 1.602 × 10 − 19 ) 2 C 2 4 × 3.14 × 8.854 × 10 − 12 J − 1 ⋅ C 2 ⋅ m − 1 × 53 × 10 − 12 m = − 2.566 × 10 − 38 5893

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Chapter F, Problem A.40E

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Interpretation:

Energy that is released has to be calculated if an electron is brought from a distance of infinity to 53 pm from a proton and also the energy difference between the accepted and calculated value has to be accounted.

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Chapter F, Problem A.39E

Chapter F, Problem A.41E

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Ch. F - Prob. A.1AST Ch. F - Prob. A.1BST Ch. F - Prob. A.2AST Ch. F - Prob. A.2BST Ch. F - Prob. A.3AST Ch. F - Prob. A.3BST Ch. F - Prob. A.4AST Ch. F - Prob. A.4BST Ch. F - Prob. A.5AST Ch. F - Prob. A.5BST

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Energy that is released has to be calculated if an electron is brought from a distance of infinity to 53 pm from a proton and also the energy difference between the accepted and calculated value has to be accounted.

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Interpretation: Energy that is released has to be calculated if an electron is brought from a distance of infinity to 53 pm from a proton and also the energy difference between the accepted and calculated value has to be accounted.

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Chapter F Solutions

Interpretation:

Energy that is released has to be calculated if an electron is brought from a distance of infinity to 53 pm from a proton and also the energy difference between the accepted and calculated value has to be accounted.