Chapter F, Problem G.3AST

Interpretation Introduction

Interpretation:

The volume of glucose solution that contains $1.44\mu \text{mol}$ of glucose molecules with concentration of $1.25\times {10}^{-3}\text{M}$ has to be calculated.

Concept Introduction:

Molarity of the solution is defined as the number of moles of solute that is dissolved in the volume of solution in liters.  Unit of molarity is $\text{mol}\cdot {\text{L}}^{-1}$.  The equation for molarity is given as follows;

    $\text{Molarity (M)}=\frac{\text{Amount of solute in moles}}{\text{Volume of solution in liters}}$

The volume of the solution can be calculated if the concentration and amount of solute is known.