Explanation Given that 2 .20 g of CO 2 and 0 .901 g of H 2 O is produced from 1 .35 g of compound and 0 .130 g of nitrogen is produced from 0 .500 g of compound. Number of moles of carbon present in 2 .20 g of carbon dioxide is calculated as follows: n (C) = 2.20 g 44.01 g ⋅ mol − 1 × 1 mol C 1 mol CO 2 = 0.050 mol Mass of carbon present in 2 .20 g of carbon dioxide is calculated as follows: m (C) = 0.050 mol × 12.01 g ⋅ mol − 1 = 0.60 g Number of moles of hydrogen present in 0 .901 g of water is calculated as follows: n (H) = 0.901 g 18.02 g ⋅ mol − 1 × 2 mol H 1 mol H 2 O = 0.10 mol Mass of hydrogen present in 0 .901 g of water is calculated as follows: m (H) = 0.10 mol × 1.008 g ⋅ mol − 1 = 0.10 g Number of moles of nitrogen present in 0 .130 g of nitrogen is calculated as follows: n (N) = 0.130 g 28.02 g ⋅ mol − 1 × 2 mol N 1 mol N 2 = 0.0093 mol Mass of nitrogen present in 0 .130 g of nitrogen is calculated as follows: m (N) = 0.0093 mol × 14.01 g ⋅ mol − 1 = 0.130 g Mass percentage of elements: Mass percentage of carbon is determined as follows: Mass percentage of carbon = 0

7th Edition

ISBN: 9781319421175

Author: ATKINS

Publisher: MAC HIGHER

See similar textbooks

Concept explainers

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "elem…

Videos

Question

Chapter F, Problem M.21E

Interpretation Introduction

Interpretation:

Empirical formula for the compound has to be written.

Concept Introduction:

Combustion analysis is a technique that is used in order to determine the empirical formula of an organic compound. In this technique the sample is burned in oxygen resulting in formation of carbon dioxide and water. The relative amounts of water and carbon dioxide is calculated from which the empirical formula is deduced.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter F, Problem M.20E

Chapter F, Problem M.22E

Students have asked these similar questions

Provide the reasonable steps to achieve the following synthesis.

Identify which compound is more acidic. Justify your choice.

Provide the reasonable steps to achieve the following synthesis.

Chapter F Solutions

CHEMICAL PRINCIPLES (LL) W/ACCESS

Ch. F - Prob. A.1AST Ch. F - Prob. A.1BST Ch. F - Prob. A.2AST Ch. F - Prob. A.2BST Ch. F - Prob. A.3AST Ch. F - Prob. A.3BST Ch. F - Prob. A.4AST Ch. F - Prob. A.4BST Ch. F - Prob. A.5AST Ch. F - Prob. A.5BST

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Solution Summary: The author explains combustion analysis as a technique used to determine the empirical formula of an organic compound.

Concept explainers

Videos

Want to see the full answer?

Chapter F Solutions