(a) Explanation Show an ideal Stirling cycle with air as the working fluid on T − s diagram. For the given Stirling cycle with air as the working fluid, let T i , P i , v i , and s i be the temperature, pressure, specific volume and specific entropy at i t h state respectively. Write the expression of entropy change during the process 1-2. s 2 − s 1 = q 12 T H (I) Here, heat added during the process 1-2 is q 12 and temperature of the heat source is T H . Write the expression of entropy change during the process 1-2. s 2 − s 1 = c v ln T 2 T 1 + R ln v 2 v 1 (II) Here, specific heat of air at constant volume is c v , and gas constant of air is R . Write the expression of ideal gas relation for states 1 and 3. P 3 v 3 T 3 = P 1 v 1 T 1 (III) Conclusion: Substitute 750 kJ / kg for q 12 , and 1,800 K for T H in Equation (I). s 2 − s 1 = 750 kJ / kg 1 , 800 K = 0.4167 kJ / kg ⋅ K For the isothermal process 1-2, temperature remains constant, hence T 2 and T 1 are equal. Rearrange Equation (II), and substitute 0.4167 kJ / kg ⋅ K for ( s 2 − s 1 ) , 0 (b) To determine The net work output for an ideal Stirling cycle.

8th Edition

ISBN: 9780073398174

Author: Yunus A. Cengel Dr., Michael A. Boles

Publisher: McGraw-Hill Education

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Question

Chapter 9.12, Problem 163RP

(a)

To determine

The maximum pressure in an ideal Stirling cycle with air as the working fluid.

(b)

To determine

The net work output for an ideal Stirling cycle.

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Chapter 9.12, Problem 162RP

Chapter 9.12, Problem 164RP

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