
World of Chemistry
7th Edition
ISBN: 9780618562763
Author: Steven S. Zumdahl
Publisher: Houghton Mifflin College Div
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Question
Chapter 9, Problem 7A
Interpretation Introduction
Interpretation:
The mole ratios that would be used to calculate the moles of Ag2S and H2 for the given moles of Ag reacting needs to be deduced.
Concept Introduction:
- A
chemical reaction is expressed as a chemical equation having reactants and products on left and right side of the reaction arrow respectively. - The coefficient of a balanced chemical equation i.e. the stoichiometry gives the amount of reactants and products involved in the reaction.
- The stoichiometric ratio between the reactants or between reactants and products is expressed in terms of the mole-mole ratio.
Expert Solution & Answer

Answer to Problem 7A
Explanation of Solution
The given reaction is:
The balanced equation is:
Based on the reaction stoichiometry:
2 moles of Ag reacts to produce 1 mole of Ag2S and 1 mole of H2. Therefore,
Ag:Ag2S mole-mole ratio =
Ag:H2mole-mole ratio =
Conclusion
Therefore, the mole ratio factor is ½ or 0.5 for both Ag2S and H2.
Chapter 9 Solutions
World of Chemistry
Ch. 9.1 - Prob. 1RQCh. 9.1 - Prob. 2RQCh. 9.1 - Prob. 3RQCh. 9.1 - Prob. 4RQCh. 9.1 - Prob. 5RQCh. 9.2 - Prob. 1RQCh. 9.2 - Prob. 2RQCh. 9.2 - Prob. 3RQCh. 9.2 - Prob. 4RQCh. 9.2 - Prob. 5RQ
Ch. 9.2 - Prob. 6RQCh. 9.3 - Prob. 1RQCh. 9.3 - Prob. 2RQCh. 9.3 - Prob. 3RQCh. 9.3 - Prob. 4RQCh. 9.3 - Prob. 5RQCh. 9 - Prob. 1ACh. 9 - Prob. 2ACh. 9 - Prob. 3ACh. 9 - Prob. 4ACh. 9 - Prob. 5ACh. 9 - Prob. 6ACh. 9 - Prob. 7ACh. 9 - Prob. 8ACh. 9 - Prob. 9ACh. 9 - Prob. 10ACh. 9 - Prob. 11ACh. 9 - Prob. 12ACh. 9 - Prob. 13ACh. 9 - Prob. 14ACh. 9 - Prob. 15ACh. 9 - Prob. 16ACh. 9 - Prob. 17ACh. 9 - Prob. 18ACh. 9 - Prob. 19ACh. 9 - Prob. 20ACh. 9 - Prob. 21ACh. 9 - Prob. 22ACh. 9 - Prob. 23ACh. 9 - Prob. 24ACh. 9 - Prob. 25ACh. 9 - Prob. 26ACh. 9 - Prob. 27ACh. 9 - Prob. 28ACh. 9 - Prob. 29ACh. 9 - Prob. 30ACh. 9 - Prob. 31ACh. 9 - Prob. 32ACh. 9 - Prob. 33ACh. 9 - Prob. 34ACh. 9 - Prob. 35ACh. 9 - Prob. 36ACh. 9 - Prob. 37ACh. 9 - Prob. 38ACh. 9 - Prob. 39ACh. 9 - Prob. 40ACh. 9 - Prob. 41ACh. 9 - Prob. 42ACh. 9 - Prob. 43ACh. 9 - Prob. 44ACh. 9 - Prob. 45ACh. 9 - Prob. 46ACh. 9 - Prob. 47ACh. 9 - Prob. 48ACh. 9 - Prob. 49ACh. 9 - Prob. 50ACh. 9 - Prob. 51ACh. 9 - Prob. 52ACh. 9 - Prob. 53ACh. 9 - Prob. 54ACh. 9 - Prob. 55ACh. 9 - Prob. 56ACh. 9 - Prob. 57ACh. 9 - Prob. 58ACh. 9 - Prob. 59ACh. 9 - Prob. 60ACh. 9 - Prob. 61ACh. 9 - Prob. 62ACh. 9 - Prob. 63ACh. 9 - Prob. 64ACh. 9 - Prob. 65ACh. 9 - Prob. 66ACh. 9 - Prob. 67ACh. 9 - Prob. 1STPCh. 9 - Prob. 2STPCh. 9 - Prob. 3STPCh. 9 - Prob. 4STPCh. 9 - Prob. 5STPCh. 9 - Prob. 6STPCh. 9 - Prob. 7STP
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