
Concept explainers
Interpretation:
The mass of water needed to completely react with 20.0 g of PCl3 needs to be deduced based on the given reaction.
Concept Introduction:
- A
chemical reaction is expressed as a chemical equation having reactants and products on the left and right side of the reaction arrow respectively.
- The coefficient of a balanced chemical equation, i.e., the stoichiometry gives the number of reactants and products involved in the reaction.
- The stoichiometric ratio between the reactants or between reactants and products is expressed in terms of the mole-mole ratio.

Answer to Problem 18A
Mass of water = 2.62 g
Explanation of Solution
The given reaction is:
Step 1: Calculate the moles of PCl3 present as follows:
Mass of PCl3 present = 20.0 g
Molecular weight of PCl3 = 137.33 g/mole
The moles will be:
Step 2: Calculate the moles of water reacted:
Based on the reaction stoichiometry:
1 mole of PCl3 reacts with 3 moles of water.
Therefore, 0.1456 moles of PCl3 would react with:
Step 3: Calculate the mass of water needed as follows:
Moles of water reacted = 0.1456 moles
Molecular weight of H2O = 18 g/mol
Therefore, 2.62 g of water is needed to completely react with 20.0 g of PCl3.
Chapter 9 Solutions
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