
Concept explainers
Interpretation:
155 g of calcium carbonate is treated with 250 g of anhydrous hydrogen chloride and only 142 g of CaCl2 is obtained, the percentage yield of the compound should be predicted.
Concept Introduction:
The reaction in which the reactant is totally consumed when the reaction is completed isknown as limiting reactant.
The ratio of actual yield to the theoretical yield multiplied by 100 is known as percent yield.

Answer to Problem 46A
The percentage yield is 76.49%
Explanation of Solution
The given reaction is shown below:
The calculation of moles is shown below:
According to the given reaction 2 mole of HCl reacts with 1 mole of CaCO3 and produced 1
mol of CaCl2. Therefore, 4.05 moles of CaCO3 would react with 2× 4.05 = 8.1 moles of HCl
But there are 6.84 moles of HCl that means HClwill get totally consumed in the reaction and thus, will act as a limiting reactant.
Moles of H2O produced =3.42
According to the given reaction;
6 moles of H2O =1 mole of CaCl2
actual theoretical yield =3.42-0.57
= 2.85
The calculation of percentage yield is shown below:
Thus, the percentage yield is 76.49%
Chapter 9 Solutions
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