
Concept explainers
Interpretation:
The amount of iron (III) chloride formed when 15.5 mg of iron reacts with excess chlorine gas needs to be deduced based on the given reaction.
Concept Introduction:
- A
chemical reaction is expressed as a chemical equation having reactants and products on left and right side of the reaction arrow respectively. - The coefficient of a balanced chemical equation, i.e., the stoichiometry gives the number of reactants and products involved in the reaction.
- Chemical equations can therefore be used to determine the amount of products formed from a known quantity of reactants

Answer to Problem 20A
Mass of FeCl3 = 44.9 mg i.e. 45.0 mg
Explanation of Solution
The given reaction is:
The balanced equation is:
Here since Cl2 is present in excess and Fe is the limiting reagent. The amount of FeCl3 formed will be determined by the amount of Fe reacted.
Step 1: Calculate the moles of Fe present:
Mass of Fe present = 15.5mg = 0.0155 g
Atomic weight of Fe = 55.85 g/mole
Step 2: Calculate the moles of FeCl3 formed:
Based on the reaction stoichiometry:
Fe and FeCl3 are present in a 1:1 molar ratio
Therefore, 0.000277 moles of Fe would produce 0.000277 moles of FeCl3
Step 3: Calculate the mass of FeCl3 formed:
Moles of FeCl3 formed= 0.000277 moles
Molecular weight of FeCl3 = 162.2 g/mol
Therefore, mass of FeCl3 formed is around 44.9 mg.
Chapter 9 Solutions
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