
Concept explainers
(a)
Interpretation:
The number of moles and grams of ammonium chloride produced from 0.5 mole of ammonia must be calculated.
Concept Introduction:
One mole ammonia gas reacts with one mole hydrogen chloride gas to produce one mole of ammonium chloride with molar mass 53.5 g.
(a)

Answer to Problem 9A
0.5 mole of ammonium chloride will be produced. Mass of 0.5 mole ammonium chloride is 26.75 g.
Mole ratio of NH3:NH4Cl is 1:1.
Explanation of Solution
The given reaction is as follows:
From the balanced equation it is clear that complete conversion of 0.5 mole ammonia will produce 0.5 mole ammonium chloride.
Molar mass of ammonium chloride is 53.5 g.
Thus mass of 0.5 mole ammonium chloride
b)
Interpretation:
The number of moles and mass of carbon disulfide and hydrogen sulfide produced from 0.5 mole of atomic sulfur must be calculated.
Concept Introduction:
Four mole sulfur atom reacts with one mole methane gas to produce one mole of carbon disulfide with molar mass 76 g and 2 moles of hydrogen sulfide gas with molar mass 34 g.
b)

Answer to Problem 9A
0.125 mole of carbon disulfide will be produced. Mass of 0.125 mole carbon disulfide is 9.5 g.
0.25 moles of hydrogen sulfide will be produced. Mass of 0.25 moles of hydrogen sulfide is 8.5 g.
Mole ratio of S: CS2 is 4:1 and mole ratio of S: H2S is 2:1.
Explanation of Solution
The given reaction is as follows:
From the balanced equation it is clear that complete conversion of 0.5 mole sulfur will produce 0.125 mole carbon disulfide (CS2) as 4 moles S produces 1 mole CS2.
Molar mass of carbon disulfide is 76 g.
Thus mass of 0.125 mole of carbon disulfide
4 moles S produces 2 moles H2S. Thus 0.5 mol S will produce 0.25 mole of H2S.
Molar mass of hydrogen sulfide is 34 g.
Thus mass of 0.25 mole of hydrogen sulfide
c)
Interpretation:
The number of moles and mass of phosphorous acid and hydrochloric acid produced from 0.5 mole of phosphorous trichloride must be calculated.
Concept Introduction:
One mole phosphorous acid reacts with three moles of water to produce one mole of phosphorous acid with molar mass 82 g and three moles of hydrochloric acid with molar mass 36.5 g.
c)

Answer to Problem 9A
0.5 mole of phosphorous acid will be produced. Mass of 0.5 mole phosphorous acid is 41 g.
1.5 moles of hydrochloric acid will be produced. Mass of 1.5 moles of hydrochloric acid is 54.75 g.
Mole ratio of PCl3:H3PO3 is 1:1 and mole ratio of PCl3: HCl is 1:3.
Explanation of Solution
The reaction is as follows:
From the balanced equation it is clear that complete conversion of 0.5 mole PCl3 will produce 0.5 mole phosphorous acid (PCl3).
Molar mass of H3PO3 is 82 g.
Thus mass of 0.5 mole H3PO3
1 moles PCl3 produces 3 moles HCl. Thus 0.5 mol PCl3 will produce 1.5 mole of HCl.
Molar mass of HCl is 36.5 g.
Thus mass of 1.5 moles of HCl
d)
Interpretation:
The number of moles and grams of sodium bicarbonate produced from 0.5 mole of sodium hydroxide must be calculated.
Concept Introduction:
One mole sodium hydroxide reacts with one mole of carbon dioxide to produce one mole of sodium bicarbonate with molar mass 84 g.
d)

Answer to Problem 9A
0.5 mole of sodium bicarbonate will be produced. Mass of 0.5 mole sodium bicarbonate is 42 g.
Mole ratio of NaOH: NaHCO3 is 1:1.
Explanation of Solution
The reaction is as follows:
From the balanced equation it is clear that complete conversion of 0.5 mole NaOH will produce 0.5 mole NaHCO3
Molar mass of NaHCO3 is 84 g.
Thus mass of 0.5 mole NaHCO3
Chapter 9 Solutions
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