(a)
Interpretation:
Given species has to be rank from best nucleophile to the poorest nucleophile.
Concept Introduction:
Aprotic solvent are polar solvent molecules which do not have hydrogen bonded to oxygen to nitrogen.
Protic solvent are polar solvent molecules which have hydrogen bonded to oxygen to nitrogen.
The stronger base is always a better nucleophile in an aprotic solvent. When the negatively charged species is placed in aprotic solvent, the solvent molecules arrange themselves with their partially positively charged hydrogens pointing towards the negatively charged species. The interaction between the ion and the dipole of the protic solvent is called an ion-dipole interaction
(b)
Interpretation:
Given species has to be rank from best nucleophile to the poorest nucleophile.
Concept Introduction:
Aprotic solvent are polar solvent molecules which do not have hydrogen bonded to oxygen to nitrogen.
The stronger base is always a better nucleophile in an aprotic solvent.
(c)
Interpretation:
Given species has to be rank from best nucleophile to the poorest nucleophile.
Concept Introduction:
Aprotic solvent are polar solvent molecules which do not have hydrogen bonded to oxygen to nitrogen.
Protic solvent are polar solvent molecules which have hydrogen bonded to oxygen to nitrogen
The stronger base is always a better nucleophile in an aprotic solvent. When the negatively charged species is placed in aprotic solvent, the solvent molecules arrange themselves with their partially positively charged hydrogens pointing towards the negatively charged species. The interaction between the ion and the dipole of the protic solvent is called an ion-dipole interaction
(d)
Interpretation:
Given species has to be rank from best nucleophile to the poorest nucleophile.
Concept Introduction:
Aprotic solvent are polar solvent molecules which do not have hydrogen bonded to oxygen to nitrogen.
Protic solvent are polar solvent molecules which do have hydrogen bonded to oxygen to nitrogen
The stronger base is always a better nucleophile in an aprotic solvent.
When the negatively charged species is placed in aprotic solvent, the solvent molecules arrange themselves with their partially positively charged hydrogens pointing towards the negatively charged species. The interaction between the ion and the dipole of the protic solvent is called an ion-dipole interaction.
Want to see the full answer?
Check out a sample textbook solution
Chapter 9 Solutions
Organic Chemistry
- Briefly indicate the structure and bonding of silicates.arrow_forward4 Part C Give the IUPAC name and a common name for the following ether: Spell out the full names of the compound in the indicated order separated by a comma.arrow_forwardTry: Draw possible resonance contributing structures for the following organic species: CH3CH2NO2 [CH2CHCH2] [CH2CHCHO] [CH2CHCH2] [CH2CHNH2]arrow_forward
- Complete the following synthesis. (d). H+ ง сarrow_forwardCan the target compound be efficiently synthesized in good yield from the substituted benzene of the starting material? If yes, draw the synthesis. Include all steps and all reactants.arrow_forwardThis is a synthesis question. Why is this method wrong or worse than the "correct" method? You could do it thiss way, couldn't you?arrow_forward
- Try: Draw the best Lewis structure showing all non-bonding electrons and all formal charges if any: (CH3)3CCNO NCO- HN3 [CH3OH2]*arrow_forwardWhat are the major products of the following reaction? Draw all the major products. If there are no major products, then there is no reaction that will take place. Use wedge and dash bonds when necessary.arrow_forwardZeolites. State their composition and structure. Give an example.arrow_forward
- Don't used hand raiting and show all reactionsarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forwardIX) By writing the appropriate electron configurations and orbital box diagrams briefly EXPLAIN in your own words each one of the following questions: a) The bond length of the Br2 molecule is 2.28 Å, while the bond length of the compound KBr is 3.34 Å. The radius of K✶ is 1.52 Å. Determine the atomic radius in Å of the bromine atom and of the bromide ion. Br = Br b) Explain why there is a large difference in the atomic sizes or radius of the two (Br and Br). Tarrow_forward
ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
ChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill Education
Principles of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill Education
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY