Concept explainers
Har Gobind Khorana and his colleagues performed numerous experiments translating synthetic
Write the sequence of this
What is the sequence of the resulting polypeptide?
How did the polypeptide composition help confirm thetriplet nature of the genetic code?
If the genetic code were a doublet code instead of atriplet code, how would the result of this experiment be different?
If the genetic code was overlapping rather than non-overlapping, how would the result of this experiment bedifferent?
Want to see the full answer?
Check out a sample textbook solutionChapter 9 Solutions
Genetic Analysis: An Integrated Approach (3rd Edition)
- Decode the unknown word using the genetic code and fill out the missing nucleotides. Translate the generated mRNA sequence using the universal genetic code table and the information derived from the previous steps. Determine the unknown word by arranging the single letter amino acid code of the hypothetical protein produced bound by the start and stop codon.arrow_forwardConsider the following DNA sequence, which codes for a short polypeptide: 5'-ATGGGCTTAGCGTAGGTTAGT-3' Determine the mRNA transcript of this sequence. You have to write these sequences from the 5' end to the 3' end and indicate those ends as shown in the original sequence in order to get the full mark. How many amino acids will make up this polypeptide? Determine the first four anticodons that will be used in order to translate this sequence.arrow_forwardKnowing that the genetic code is almost universal, a scientist uses molecular biological methods to insert the human β-globin gene (Shown in Figure 17.11) into bacterial cells, hoping the cells will express it and synthesize functional β-globin protein. Instead, the protein produced is nonfunctional and is found to contain many fewer amino acids than does β-globin made by a eukaryotic cell. Explain why.arrow_forward
- The following is a portion of an mRNA sequence: 3’ –AUCGUCAUGCAGA-5’ a)During transcription, was the adenine at the left-hand side of the sequence the first or the last nucleotide used to build the portion of the mRNA shown? Explain how you know. b)Write out the sequence and polarity of the DNA duplex that encodes this mRNA segment. Label the template and coding DNA strands. c)Identify the direction in which the promoter region for this gene will be located.arrow_forwardHere is a eukaryotic gene. The numbers given are base pairs of exon and intron. How long in bases will the pre mRNA transcript be? Explain briefly. What is the maximum number of amino acids that could make up the protein product from the final mRNA? Explain briefly.arrow_forwardFor each of the following items, fill in either the DNA strand, the MRNA codons, the tRNA anticodons, or the amino acid sequence that have been left blank. If several sequences might work, choose only one. Furthermore, circle the start and the stop codons of each mRNA sequence. 1. DNA (3'-5') ACG TAC GGC CGG TTA AAG CAT ACT TTC TTG MRNA TRNA Amino Acid 2. DNA (3'-5') MRNA AUG ACU AGC UGG GGG UAU UAC UUU UAG AAA TRNA Amino Acid 3. DNA (3'-5') MRNA TRNA GCU CCU UAC CAC ССС CGU AUG GCU GGG AUC Activate Go to Sett Amino Acidarrow_forward
- The genetic code was solved partly by the use of in vitro systems to translate synthetic RNAs into peptides. In these systems, ribosomes, amino acids, and buffers that support translation are added and there is no control of where translation begins. AAA = Lys; AUA = Ile; AAU = Asn; UAA = stop. What peptides would NOT be produced in an in vitro system if the following oligonucleotide were added: AAAAAAAAAUAAAAAAAA Select one: a) Lys-Lys-Lys-Lys-Lys-Lys-Lys-Lys b) Lys-Lys-Ile-Lys-Lys c) Lys-Lys-Asn-Lys-Lysarrow_forwardThe gene ABCD is 1500 bases long. Answer the following questions: What would be the likely length of the pre-mRNA molecule? What would be the likely length of the mature RNA molecule? What would be the likely length of the protein?arrow_forwardDecode the unknown word using the genetic code and fill out the missing nucleotides. Translate the generated mRNA sequence using the universal genetic code table and the information derived from the previous steps. Determine the unknown word by arranging the single letter amino acid code of the hypothetical protein produced bound by the start and stop codon.arrow_forward
- Decode the unknown word using the genetic code and fill out the missing nucleotides. Translate the generated mRNA sequence using the universal genetic code table and the information derived from the previous steps. . determine the unknown word by arranging the single letter amino acid code of the hypothetical protein produced bound by the start and stop codon.arrow_forwardConsider this nucleotide sequence of DNA strand in the image provided. If this strand is the sense strand, Give the correct nucleotide sequence of the RNA produced after transcription. If the RNA formed in #1 is already a functional mRNA and will be used to synthesize proteins, how many codons are present here that will actually code for amino acids? What is the sequence of the stop codon in this mRNA? What is the sequence of the 3rd codon in this mRNA? What is the sequence of the last codon in this mRNA that actually code for an amino acid?arrow_forwardConsider the following coding 71 nucleotide DNA template sequence (It does not contain a translational start): 5’- GTTTCCCCTATGCTTCATCACGAGGGCACTGACATGTGTAAACGAAATTCCAACCTGAGCGGCGT GTTGAG-3’ By in vitro translating the mRNA, you determined that the translated peptide is 15 amino acids long. What is the expected peptide sequence in single letter abbreviations?arrow_forward
- Biology: The Dynamic Science (MindTap Course List)BiologyISBN:9781305389892Author:Peter J. Russell, Paul E. Hertz, Beverly McMillanPublisher:Cengage Learning