Inquiry into Physics
8th Edition
ISBN: 9781337515863
Author: Ostdiek
Publisher: Cengage
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Chapter 9, Problem 19P
To determine
The fractional change in scattering of light due to atmosphere when
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No chatgpt pls will upvote
is 0.3026 a finite number
Plastic beads can often carry a small charge and therefore can generate electric fields. Three beads are oriented such that
system of all three beads is zero.
91
E field lines
93
92
What charge does each bead carry?
91
92
-1.45
=
=
What is the net charge of the system? What charges have to be equal? μC
2.9
×
What is the net charge of the system? What charges have to be equal? μC
93 = 2.9
μС
92
is between and
91 93°
The sum of the charge on q₁ and 92 is 91 + 92 = −2.9 μC, and the net charge of the
Chapter 9 Solutions
Inquiry into Physics
Ch. 9 - Give three advantages that the Fresnel lens design...Ch. 9 - Prob. 2OEACh. 9 - Prob. 1PIPCh. 9 - Thomas Young’s conception of the fundamental...Ch. 9 - The shell” of a concept map dealing with lenses...Ch. 9 - Sections 9.6 and 9.7 deal with the phenomena of...Ch. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 2QCh. 9 - Prob. 3QCh. 9 - Prob. 4Q
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- Plastic beads can often carry a small charge and therefore can generate electric fields. Three beads are oriented such that 92 is between q₁ and 93. The sum of the charge on 9₁ and 92 is 9₁ + 92 = −2.9 µС, and the net charge of the system of all three beads is zero. E field lines 93 92 What charge does each bead carry? 91 92 -1.45 What is the net charge of the system? What charges have to be equal? μC 2.9 ✓ What is the net charge of the system? What charges have to be equal? μC 93 2.9 μεarrow_forwardNo chatgpt pls will upvotearrow_forwardPoint charges of 6.50 μC and -2.50 μC are placed 0.300 m apart. (Assume the negative charge is located to the right of the positive charge. Include the sign of the value in your answers.) (a) Where can a third charge be placed so that the net force on it is zero? 0.49 m to the right of the -2.50 μC charge (b) What if both charges are positive? 0.49 xm to the right of the 2.50 μC chargearrow_forward
- Find the electric field at the location of q, in the figure below, given that q₁ =9c9d = +4.60 nC, q = -1.00 nC, and the square is 20.0 cm on a side. (The +x axis is directed to the right.) magnitude direction 2500 x What symmetries can you take advantage of? What charges are the same magnitude and the same distance away? N/C 226 × How does charge sign affect the direction of the electric field? counterclockwise from the +x-axis 9a 9b % 9 9darrow_forwardwould 0.215 be the answer for part b?arrow_forwardSuppose a toy boat moves in a pool at at a speed given by v=1.0 meter per second at t=0, and that the boat is subject to viscous damping. The damping on the boat causes the rate of speed loss to be given by the expression dv/dt=-2v. How fast will the boat be traveling after 1 second? 3 seconds? 10 seconds? Use separation of variables to solve this.arrow_forward
- What functional form do you expect to describe the motion of a vibrating membrane without damping and why?arrow_forwardIf speed is tripled, how much larger will air drag become for an object? Show the math.arrow_forwardWhat does it tell us about factors on which air drag depends if it is proportional to speed squared?arrow_forward
- What is the net charge on a sphere that has the following? x (a) 5.75 × 106 electrons and 8.49 × 106 protons 4.39e-13 What is the charge of an electron? What is the charge of a proton? C (b) 200 electrons and 109 protons 1.60e-10 What is the charge of an electron? What is the charge of a proton? Carrow_forwardA spider begins to spin a web by first hanging from a ceiling by his fine, silk fiber. He has a mass of 0.025 kg and a charge of 3.5 μC. A second spider with a charge of 4.2 μC rests in her own web exactly 2.1 m vertically below the first spider. (a) What is the magnitude of the electric field due to the charge on the second spider at the position of the first spider? 8.57e3 N/C (b) What is the tension in the silk fiber above the first spider? 0.125 How does the electric field relate to the force? How do you calculate the net force? Narrow_forwardPoint charges of 6.50 μC and -2.50 μC are placed 0.300 m apart. (Assume the negative charge is located to the right of the positive charge. Include the sign of the value in your answers.) (a) Where can a third charge be placed so that the net force on it is zero? 0.49 m to the right of the -2.50 μC charge (b) What if both charges are positive? 0.185 xm to the right of the 2.50 μC chargearrow_forward
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