Inquiry into Physics
8th Edition
ISBN: 9781337515863
Author: Ostdiek
Publisher: Cengage
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Textbook Question
Chapter 9, Problem 12Q
(Indicates a review question, which means it requires only a basic understanding of the material to answer. Questions without this designation typically involve integrating or extending the concepts presented thus far.)
. What is polarized light? How do Polaroid sunglasses exploit polanzation?
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No chatgpt pls will upvote
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Chapter 9 Solutions
Inquiry into Physics
Ch. 9 - Give three advantages that the Fresnel lens design...Ch. 9 - Prob. 2OEACh. 9 - Prob. 1PIPCh. 9 - Thomas Young’s conception of the fundamental...Ch. 9 - The shell” of a concept map dealing with lenses...Ch. 9 - Sections 9.6 and 9.7 deal with the phenomena of...Ch. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 2QCh. 9 - Prob. 3QCh. 9 - Prob. 4Q
Ch. 9 - Prob. 5QCh. 9 - Prob. 6QCh. 9 - Prob. 7QCh. 9 - Prob. 8QCh. 9 - Prob. 9QCh. 9 - Prob. 10QCh. 9 - Prob. 11QCh. 9 - (Indicates a review question, which means it...Ch. 9 - (Indicates a review question, which means it...Ch. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 15QCh. 9 - Prob. 16QCh. 9 - (Indicates a review question, which means it...Ch. 9 - (Indicates a review question, which means it...Ch. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 20QCh. 9 - Prob. 21QCh. 9 - Prob. 22QCh. 9 - Prob. 23QCh. 9 - Prob. 24QCh. 9 - Prob. 25QCh. 9 - Prob. 26QCh. 9 - Prob. 27QCh. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 29QCh. 9 - Prob. 30QCh. 9 - Prob. 31QCh. 9 - Prob. 32QCh. 9 - Prob. 33QCh. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 35QCh. 9 - Prob. 36QCh. 9 - Prob. 37QCh. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 39QCh. 9 - Prob. 40QCh. 9 - Prob. 41QCh. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 43QCh. 9 - Prob. 44QCh. 9 - Prob. 45QCh. 9 - Prob. 46QCh. 9 - Prob. 47QCh. 9 - Prob. 48QCh. 9 - Prob. 49QCh. 9 - Prob. 50QCh. 9 - Prob. 51QCh. 9 - Prob. 52QCh. 9 - Prob. 53QCh. 9 - Prob. 54QCh. 9 - Prob. 55QCh. 9 - Prob. 56QCh. 9 - Prob. 57QCh. 9 - Prob. 58QCh. 9 - Prob. 59QCh. 9 - Prob. 60QCh. 9 - Suppose a beam of red light from an He-Ne laser...Ch. 9 - In a double-slit interference experiment, a...Ch. 9 - A light ray traveling in air strikes the surface...Ch. 9 - A ray of yellow light crosses the boundary between...Ch. 9 - Prob. 5PCh. 9 - A fish looks up toward the surface of a pond and...Ch. 9 - A camera is equipped with a lens with a focal...Ch. 9 - A 2.0-cm-tall object stands in front of a...Ch. 9 - When viewed through a magnifying glass, a stamp...Ch. 9 - . A person looks at a statue that is 2 m tall. The...Ch. 9 - Prob. 11PCh. 9 - . A small object is placed to the left of a convex...Ch. 9 - . If the object in Problem 12 is moved toward the...Ch. 9 - . (a) In a camera equipped with a 50-mm...Ch. 9 - . The focal length of a diverging lens is...Ch. 9 - . The equation connecting s, p, and f for a simple...Ch. 9 - . If the mirror described in the previous problem...Ch. 9 - Prob. 18PCh. 9 - Prob. 19PCh. 9 - Prob. 1CCh. 9 - In Section 9.6, we described how the speed of...Ch. 9 - Would the critical angle for a glass—water...Ch. 9 - Prob. 4CCh. 9 - Prob. 5CCh. 9 - Prob. 6CCh. 9 - Prob. 7CCh. 9 - Prob. 8CCh. 9 - Prob. 9CCh. 9 - Prob. 10C
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- Plastic beads can often carry a small charge and therefore can generate electric fields. Three beads are oriented such that 92 is between q₁ and 93. The sum of the charge on 9₁ and 92 is 9₁ + 92 = −2.9 µС, and the net charge of the system of all three beads is zero. E field lines 93 92 What charge does each bead carry? 91 92 -1.45 What is the net charge of the system? What charges have to be equal? μC 2.9 ✓ What is the net charge of the system? What charges have to be equal? μC 93 2.9 μεarrow_forwardNo chatgpt pls will upvotearrow_forwardPoint charges of 6.50 μC and -2.50 μC are placed 0.300 m apart. (Assume the negative charge is located to the right of the positive charge. Include the sign of the value in your answers.) (a) Where can a third charge be placed so that the net force on it is zero? 0.49 m to the right of the -2.50 μC charge (b) What if both charges are positive? 0.49 xm to the right of the 2.50 μC chargearrow_forward
- Find the electric field at the location of q, in the figure below, given that q₁ =9c9d = +4.60 nC, q = -1.00 nC, and the square is 20.0 cm on a side. (The +x axis is directed to the right.) magnitude direction 2500 x What symmetries can you take advantage of? What charges are the same magnitude and the same distance away? N/C 226 × How does charge sign affect the direction of the electric field? counterclockwise from the +x-axis 9a 9b % 9 9darrow_forwardwould 0.215 be the answer for part b?arrow_forwardSuppose a toy boat moves in a pool at at a speed given by v=1.0 meter per second at t=0, and that the boat is subject to viscous damping. The damping on the boat causes the rate of speed loss to be given by the expression dv/dt=-2v. How fast will the boat be traveling after 1 second? 3 seconds? 10 seconds? Use separation of variables to solve this.arrow_forward
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- What is the net charge on a sphere that has the following? x (a) 5.75 × 106 electrons and 8.49 × 106 protons 4.39e-13 What is the charge of an electron? What is the charge of a proton? C (b) 200 electrons and 109 protons 1.60e-10 What is the charge of an electron? What is the charge of a proton? Carrow_forwardA spider begins to spin a web by first hanging from a ceiling by his fine, silk fiber. He has a mass of 0.025 kg and a charge of 3.5 μC. A second spider with a charge of 4.2 μC rests in her own web exactly 2.1 m vertically below the first spider. (a) What is the magnitude of the electric field due to the charge on the second spider at the position of the first spider? 8.57e3 N/C (b) What is the tension in the silk fiber above the first spider? 0.125 How does the electric field relate to the force? How do you calculate the net force? Narrow_forwardPoint charges of 6.50 μC and -2.50 μC are placed 0.300 m apart. (Assume the negative charge is located to the right of the positive charge. Include the sign of the value in your answers.) (a) Where can a third charge be placed so that the net force on it is zero? 0.49 m to the right of the -2.50 μC charge (b) What if both charges are positive? 0.185 xm to the right of the 2.50 μC chargearrow_forward
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