Concept explainers
The angle of refraction when light passes from air to glass with help of given figure
Answer to Problem 5P
Explanation of Solution
Calculation:
This is figure 9.34.
When we closely observe the figure, we can estimate the angle of refraction. So, we can see the following estimation as
Here, we can observe that as the angle of incidence increases, angle of refraction also increases. So, we can see that if we do the angle of incidence double, then, angle of refraction also be double.
Similarly, if we angle of incidence is
When we see the figure, we can also get angle of refraction as
Conclusion:
Thus, angle of incident changes as the angle of refraction.
Want to see more full solutions like this?
Chapter 9 Solutions
Inquiry into Physics
- A light ray is traveling through air (n=1.00) at an angle of 65 degrees until it enters a fresh water lake (n=1.33). What is the angle (in degrees) of the refracted light in the lake? Keep all of your calculations rounded to atleast 2-3 decimal places until the final answer, in order to calculate the correct answer.arrow_forwardray of light strikes a flat block of glass at an incidence angle of ?1 = 38.6°. The glass is 2.00 cm thick and has an index of refraction that equals ng = 1.52. a.)What is the angle of refraction, ?2, that describes the light ray after it enters the glass from above? (Enter your answer in degrees to at least 2 decimal places.) b.) With what angle of incidence, ?3, does the ray approach the interface at the bottom of the glass? (Enter your answer in degrees to at least 2 decimal places.) c.) With what angle of refraction, ?4, does the ray emerge from the bottom of the glass? (Enter your answer in degrees to at least 1 decimal place.) d.) The distance d separates the twice-bent ray from the path it would have taken without the glass in the way. What is this distance (in cm)? e.) At what speed (in m/s) does the light travel within the glass? f.) How many nanoseconds does the light take to pass through the glass along the angled path shown here?arrow_forwardA ray of light traveling in air strikes the surface of a certain plastic slab (with unknown index of refraction) at 54.0 degrees with respect to the normal in air. travels in the plastic slab at 23.0 degrees with respect to the normal. Part a: calculate the index of refraction of the plastic material. It the value as odd number Part b: calculate the critical angle of the plastic material in air . Report this numerical value along with your work that lead to it in the even numberedarrow_forward
- Calculate the speed of light in fused quartz. What percent is this of the speed of light in vacuum? The index of refraction of a fused quartz is n = 1.458. Express your answer in 2 decimal places.arrow_forwardExercise 56: An incident ray hits a face of an equilateral prism perpendicularly (figure 4.86). What is the minimum value of the refractive index of the prism if there is total internal reflection on the second face? Answer: 1.15 m *Please show steps and explanation for my understanding. Thank youarrow_forwardThe prism in the figure below is made of glass with an index of refraction of 1.63 for blue light and 1.61 for red light. Find ?R, the angle of deviation for red light, and ?B, the angle of deviation for blue light, if white light is incident on the prism at an angle of 30.0°. (Enter your answers in degrees.) see image attached (a) ?R, the angle of deviation for red light (b) ?B, the angle of deviation for blue lightarrow_forward
- Use the exact values you enter to make later calculations.A ray of light strikes a flat, 2.00-cm-thick block of glass (n = 1.96) at an angle of ? = 32.4° with respect to the normal (see figure below). A light ray incident on a glass block of thickness 2.00 cm is shown. The ray travels down and to the right and is incident to the top of the block at an angle ? to the normal of the surface. The ray inside the block moves down and to the right but at a steeper slope than the incident ray. It is incident on the bottom surface of the block and exits moving down and to the right, in the same direction as the incident ray. A dashed line extends from the original path of the ray down in the block and is shown to be a distance d from the ray that exits the glass block. (a) Find the angle of refraction at the top surface and the angle of incidence at the bottom surface. °(b) Find the refracted angle at the bottom surface. °(c) Find the lateral distance d by which the light beam is shifted. cm(d)…arrow_forwardA piece of jewelry consists of a sphere of quartz (n-1.5) embedded on a zircon (n-1.8) base as shown in the figure. A light ray traveling through the zircon strikes the spherical piece of quartz at an angle of incidence 8, as shown below. Which is the probable path that the ray of light could follow? Assume all incident angles are below their respective critical angles. The normals at each boundary are shown. Zircon n=1.8 Quartz n=1.5 Air n=1.0 A B CD m w u < 00000arrow_forwardAnswer must be in standard form scientific notation with SI units that do not have prefixes except for kg. Provide the answer with the correct amount of significant figures. Thank you so much I greatly appreciate itarrow_forward
- A ray of light strikes a surface at an angle of 72.2° with respect to the normal. Use your knowledge on reflection and refraction of light to draw the reflected and/or refracted rays through the crown glass and the materials A (nA=1.6) and B (nB=1.362). Justify your answers Note: your illustration must include the significant angles such as the angles of reflection and refraction.)arrow_forwardPlease refer to part (b) of Figure 1 included. Here, theta (the angle the incident ray makes with respect to the vertical) is 37.1 degrees. What is d (the distance between the ray emerging from the bottom of the glass and where the ray would have been if it had continued straight on with no glass to refract it)? 0.29 m 1.27 m 1.67 m 0.98 marrow_forwardWhen a light ray crosses from water into glass, it emerges at an angle of 30° with respect to the normal of the interface. What is its angle of incidence? I used Snell's Law to find the angle of incidence as 34.8 degrees (rounded to 3 sig fig), using index of refraction for water as 1.333 and for glass as 1.52. However, the answer was marked as wrong. Could you please explain steps for solving to get theta as approximately 42 degrees?arrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON