Inquiry into Physics
8th Edition
ISBN: 9781337515863
Author: Ostdiek
Publisher: Cengage
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Chapter 9, Problem 54Q
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To explain the glass-air interface in the given prisms.
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Chapter 9 Solutions
Inquiry into Physics
Ch. 9 - Give three advantages that the Fresnel lens design...Ch. 9 - Prob. 2OEACh. 9 - Prob. 1PIPCh. 9 - Thomas Young’s conception of the fundamental...Ch. 9 - The shell” of a concept map dealing with lenses...Ch. 9 - Sections 9.6 and 9.7 deal with the phenomena of...Ch. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 2QCh. 9 - Prob. 3QCh. 9 - Prob. 4Q
Ch. 9 - Prob. 5QCh. 9 - Prob. 6QCh. 9 - Prob. 7QCh. 9 - Prob. 8QCh. 9 - Prob. 9QCh. 9 - Prob. 10QCh. 9 - Prob. 11QCh. 9 - (Indicates a review question, which means it...Ch. 9 - (Indicates a review question, which means it...Ch. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 15QCh. 9 - Prob. 16QCh. 9 - (Indicates a review question, which means it...Ch. 9 - (Indicates a review question, which means it...Ch. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 20QCh. 9 - Prob. 21QCh. 9 - Prob. 22QCh. 9 - Prob. 23QCh. 9 - Prob. 24QCh. 9 - Prob. 25QCh. 9 - Prob. 26QCh. 9 - Prob. 27QCh. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 29QCh. 9 - Prob. 30QCh. 9 - Prob. 31QCh. 9 - Prob. 32QCh. 9 - Prob. 33QCh. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 35QCh. 9 - Prob. 36QCh. 9 - Prob. 37QCh. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 39QCh. 9 - Prob. 40QCh. 9 - Prob. 41QCh. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 43QCh. 9 - Prob. 44QCh. 9 - Prob. 45QCh. 9 - Prob. 46QCh. 9 - Prob. 47QCh. 9 - Prob. 48QCh. 9 - Prob. 49QCh. 9 - Prob. 50QCh. 9 - Prob. 51QCh. 9 - Prob. 52QCh. 9 - Prob. 53QCh. 9 - Prob. 54QCh. 9 - Prob. 55QCh. 9 - Prob. 56QCh. 9 - Prob. 57QCh. 9 - Prob. 58QCh. 9 - Prob. 59QCh. 9 - Prob. 60QCh. 9 - Suppose a beam of red light from an He-Ne laser...Ch. 9 - In a double-slit interference experiment, a...Ch. 9 - A light ray traveling in air strikes the surface...Ch. 9 - A ray of yellow light crosses the boundary between...Ch. 9 - Prob. 5PCh. 9 - A fish looks up toward the surface of a pond and...Ch. 9 - A camera is equipped with a lens with a focal...Ch. 9 - A 2.0-cm-tall object stands in front of a...Ch. 9 - When viewed through a magnifying glass, a stamp...Ch. 9 - . A person looks at a statue that is 2 m tall. The...Ch. 9 - Prob. 11PCh. 9 - . A small object is placed to the left of a convex...Ch. 9 - . If the object in Problem 12 is moved toward the...Ch. 9 - . (a) In a camera equipped with a 50-mm...Ch. 9 - . The focal length of a diverging lens is...Ch. 9 - . The equation connecting s, p, and f for a simple...Ch. 9 - . If the mirror described in the previous problem...Ch. 9 - Prob. 18PCh. 9 - Prob. 19PCh. 9 - Prob. 1CCh. 9 - In Section 9.6, we described how the speed of...Ch. 9 - Would the critical angle for a glass—water...Ch. 9 - Prob. 4CCh. 9 - Prob. 5CCh. 9 - Prob. 6CCh. 9 - Prob. 7CCh. 9 - Prob. 8CCh. 9 - Prob. 9CCh. 9 - Prob. 10C
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- Fig. 1 shows a laser beam incident on a piece of wet filter paper placed on a glass plate whose 'refractive indexglass plate whose refractive index is to be measured (the rays are represented in the figure). Explain what happens anddeduce an expression for ni in terms of R and d. Consider the refractive index of air to be 1.Note: Remember that all light that falls on a reflecting surface always has part of the light reflected, being refracted or not.refracted or not. Moreover, θc in the figure represents the critical angle at which we have the condition of total internal reflectionarrow_forwardCrystal lattices can be examined with X-rays but not UV. Why?arrow_forwardThe two prisms shown in Fig. 7.3 are made of glass.A ray of red light enters each prism from the air, as shown.The critical angle for red light at the glass-air boundary is 42 degrees.On Fig. 7.3, complete the paths of the rays through the prisms and out into the air again.arrow_forward
- Look at the central transparent area of someone’s eye, the pupil, in normal room light. Estimate the diameter of the pupil. Now turn off the lights and darken the room. After a few minutes turn on the lights and promptly estimate the diameter of the pupil. What happens to the pupil as the eye adjusts to the room light? Explain your observations.arrow_forwardA small drop of water that is free to fall in air will contract into a spherical ball. Suppose that sunlight (this will be as if from infinity) passes into the drop. Approximately where will an image of the Sun form? Water has an index of refraction of about 1.33 for visible light, and to answer this question consider what happens when light passes through the first surface from air into the water. Where does it go? Hint: If in doubt about your math, try an experiment at home. You can use sunlight or a distant flashlight to illuminate a suspended water drop. At the back surface of the drop. Spherical drops cannot form an image. Close to the back far side of the drop, on the outside. Close to the back side of the drop, on the insidearrow_forwardthe air? Problems 1.3 Show that the two rays that enter the system in Fig. P.4.39 parallel to each other emerge from it being parallel. (start from Eq.1.31) Figure P.4.39arrow_forward
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