To estimate: The value of the magnification shown in figures 9.45, 9.48, 9.49.

Question

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Answer 1

Question

Chapter 9, Problem 44Q

To determine

To estimate:

The value of the magnification shown in figures 9.45, 9.48, 9.49.

Expert Solution & Answer

Explanation of Solution

Given:

Inquiry into Physics, Chapter 9, Problem 44Q , additional homework tip 1

Figure 9.45

Inquiry into Physics, Chapter 9, Problem 44Q , additional homework tip 2

Figure 9.48

Inquiry into Physics, Chapter 9, Problem 44Q , additional homework tip 3

Figure 9.49

Formula used:

Magnification, m=vu, 1v−1u=1f

where m is magnification v is image height u is objectheight.

Calculation:

For figure 9.45:

v=pu=−sm=−ps=1−pfs>p, so magnification is less than 1 value of magnification1v−1u=1f1p−1−s=1f1+ps=pf ⇒ ps=pf−1

For figure 9.48:

v=−pu=−sm=−p−s=ps=pf+1s<p, so magnification is greater than 1 value of magnification1v−1u=1f1−p−1−s=1f−1+ps=pf ⇒ ps=pf+1

For figure 9.49:

v=−pu=−sm=−p−s=ps=1−pfs>p, so magnification is less than 1 value of magnification1v+1u=−1f1−p+1−s=−1f−1+ps=−pf ⇒ ps=1−pf.

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Answer 2

Question

Chapter 9, Problem 44Q

To determine

To estimate:

The value of the magnification shown in figures 9.45, 9.48, 9.49.

Expert Solution & Answer

Explanation of Solution

Given:

Inquiry into Physics, Chapter 9, Problem 44Q , additional homework tip 1

Figure 9.45

Inquiry into Physics, Chapter 9, Problem 44Q , additional homework tip 2

Figure 9.48

Inquiry into Physics, Chapter 9, Problem 44Q , additional homework tip 3

Figure 9.49

Formula used:

Magnification, m=vu, 1v−1u=1f

where m is magnification v is image height u is objectheight.

Calculation:

For figure 9.45:

v=pu=−sm=−ps=1−pfs>p, so magnification is less than 1 value of magnification1v−1u=1f1p−1−s=1f1+ps=pf ⇒ ps=pf−1

For figure 9.48:

v=−pu=−sm=−p−s=ps=pf+1s<p, so magnification is greater than 1 value of magnification1v−1u=1f1−p−1−s=1f−1+ps=pf ⇒ ps=pf+1

For figure 9.49:

v=−pu=−sm=−p−s=ps=1−pfs>p, so magnification is less than 1 value of magnification1v+1u=−1f1−p+1−s=−1f−1+ps=−pf ⇒ ps=1−pf.

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Answer 3

Question

Chapter 9, Problem 44Q

To determine

To estimate:

The value of the magnification shown in figures 9.45, 9.48, 9.49.

Expert Solution & Answer

Explanation of Solution

Given:

Inquiry into Physics, Chapter 9, Problem 44Q , additional homework tip 1

Figure 9.45

Inquiry into Physics, Chapter 9, Problem 44Q , additional homework tip 2

Figure 9.48

Inquiry into Physics, Chapter 9, Problem 44Q , additional homework tip 3

Figure 9.49

Formula used:

Magnification, m=vu, 1v−1u=1f

where m is magnification v is image height u is objectheight.

Calculation:

For figure 9.45:

v=pu=−sm=−ps=1−pfs>p, so magnification is less than 1 value of magnification1v−1u=1f1p−1−s=1f1+ps=pf ⇒ ps=pf−1

For figure 9.48:

v=−pu=−sm=−p−s=ps=pf+1s<p, so magnification is greater than 1 value of magnification1v−1u=1f1−p−1−s=1f−1+ps=pf ⇒ ps=pf+1

For figure 9.49:

v=−pu=−sm=−p−s=ps=1−pfs>p, so magnification is less than 1 value of magnification1v+1u=−1f1−p+1−s=−1f−1+ps=−pf ⇒ ps=1−pf.

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Answer 4

Question

Chapter 9, Problem 44Q

To determine

To estimate:

The value of the magnification shown in figures 9.45, 9.48, 9.49.

Expert Solution & Answer

Explanation of Solution

Given:

Inquiry into Physics, Chapter 9, Problem 44Q , additional homework tip 1

Figure 9.45

Inquiry into Physics, Chapter 9, Problem 44Q , additional homework tip 2

Figure 9.48

Inquiry into Physics, Chapter 9, Problem 44Q , additional homework tip 3

Figure 9.49

Formula used:

Magnification, m=vu, 1v−1u=1f

where m is magnification v is image height u is objectheight.

Calculation:

For figure 9.45:

v=pu=−sm=−ps=1−pfs>p, so magnification is less than 1 value of magnification1v−1u=1f1p−1−s=1f1+ps=pf ⇒ ps=pf−1

For figure 9.48:

v=−pu=−sm=−p−s=ps=pf+1s<p, so magnification is greater than 1 value of magnification1v−1u=1f1−p−1−s=1f−1+ps=pf ⇒ ps=pf+1

For figure 9.49:

v=−pu=−sm=−p−s=ps=1−pfs>p, so magnification is less than 1 value of magnification1v+1u=−1f1−p+1−s=−1f−1+ps=−pf ⇒ ps=1−pf.

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Answer 5

Chapter 9, Problem 44Q

To determine

To estimate:

The value of the magnification shown in figures 9.45, 9.48, 9.49.

Expert Solution & Answer

Explanation of Solution

Given:

Inquiry into Physics, Chapter 9, Problem 44Q , additional homework tip 1

Figure 9.45

Inquiry into Physics, Chapter 9, Problem 44Q , additional homework tip 2

Figure 9.48

Inquiry into Physics, Chapter 9, Problem 44Q , additional homework tip 3

Figure 9.49

Formula used:

Magnification, m=vu, 1v−1u=1f

where m is magnification v is image height u is objectheight.

Calculation:

For figure 9.45:

v=pu=−sm=−ps=1−pfs>p, so magnification is less than 1 value of magnification1v−1u=1f1p−1−s=1f1+ps=pf ⇒ ps=pf−1

For figure 9.48:

v=−pu=−sm=−p−s=ps=pf+1s<p, so magnification is greater than 1 value of magnification1v−1u=1f1−p−1−s=1f−1+ps=pf ⇒ ps=pf+1

For figure 9.49:

v=−pu=−sm=−p−s=ps=1−pfs>p, so magnification is less than 1 value of magnification1v+1u=−1f1−p+1−s=−1f−1+ps=−pf ⇒ ps=1−pf.

Answer 6

Chapter 9, Problem 44Q

To determine

To estimate:

The value of the magnification shown in figures 9.45, 9.48, 9.49.

Expert Solution & Answer

Explanation of Solution

Given:

Inquiry into Physics, Chapter 9, Problem 44Q , additional homework tip 1

Figure 9.45

Inquiry into Physics, Chapter 9, Problem 44Q , additional homework tip 2

Figure 9.48

Inquiry into Physics, Chapter 9, Problem 44Q , additional homework tip 3

Figure 9.49

Formula used:

Magnification, m=vu, 1v−1u=1f

where m is magnification v is image height u is objectheight.

Calculation:

For figure 9.45:

v=pu=−sm=−ps=1−pfs>p, so magnification is less than 1 value of magnification1v−1u=1f1p−1−s=1f1+ps=pf ⇒ ps=pf−1

For figure 9.48:

v=−pu=−sm=−p−s=ps=pf+1s<p, so magnification is greater than 1 value of magnification1v−1u=1f1−p−1−s=1f−1+ps=pf ⇒ ps=pf+1

For figure 9.49:

v=−pu=−sm=−p−s=ps=1−pfs>p, so magnification is less than 1 value of magnification1v+1u=−1f1−p+1−s=−1f−1+ps=−pf ⇒ ps=1−pf.

Answer 7

Chapter 9, Problem 44Q

To determine

To estimate:

The value of the magnification shown in figures 9.45, 9.48, 9.49.

Answer 8

Expert Solution & Answer

Explanation of Solution

Given:

Inquiry into Physics, Chapter 9, Problem 44Q , additional homework tip 1

Figure 9.45

Inquiry into Physics, Chapter 9, Problem 44Q , additional homework tip 2

Figure 9.48

Inquiry into Physics, Chapter 9, Problem 44Q , additional homework tip 3

Figure 9.49

Formula used:

Magnification, m=vu, 1v−1u=1f

where m is magnification v is image height u is objectheight.

Calculation:

For figure 9.45:

v=pu=−sm=−ps=1−pfs>p, so magnification is less than 1 value of magnification1v−1u=1f1p−1−s=1f1+ps=pf ⇒ ps=pf−1

For figure 9.48:

v=−pu=−sm=−p−s=ps=pf+1s<p, so magnification is greater than 1 value of magnification1v−1u=1f1−p−1−s=1f−1+ps=pf ⇒ ps=pf+1

For figure 9.49:

v=−pu=−sm=−p−s=ps=1−pfs>p, so magnification is less than 1 value of magnification1v+1u=−1f1−p+1−s=−1f−1+ps=−pf ⇒ ps=1−pf.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

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To estimate: The value of the magnification shown in figures 9.45, 9.48, 9.49.

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To estimate:

The value of the magnification shown in figures 9.45, 9.48, 9.49.

Explanation of Solution

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