The molecular formula of the given compound is to be written. The hybridization of each carbon and oxygen atom is to be determined. The geometry of each carbon and oxygen atom is to be described. Concept introduction: Mixing of atomic orbitals to form degenerate molecular orbitals is called hybridization. Hybridization state of each atom is to be calculated from the total number of sigma bond pairs and lone pairs of that atom. If there are two electron domains on an atom, then the atom is s p hybridized. s p orbitals are formed by mixing of one s and one p . If there are three electron domains on an atom, then the atom is s p 2 hybridized. s p 2 orbitals are formed by mixing of one s and two p . If there are four electron domains on an atom, then the atom is s p 3 hybridized. s p 3 orbitals are formed by mixing of one s and three p . A single bond has a sigma bond. A double bond contains a sigma bond and a pi bond. A triple bond contains a sigma bond and two pi bonds.
The molecular formula of the given compound is to be written. The hybridization of each carbon and oxygen atom is to be determined. The geometry of each carbon and oxygen atom is to be described. Concept introduction: Mixing of atomic orbitals to form degenerate molecular orbitals is called hybridization. Hybridization state of each atom is to be calculated from the total number of sigma bond pairs and lone pairs of that atom. If there are two electron domains on an atom, then the atom is s p hybridized. s p orbitals are formed by mixing of one s and one p . If there are three electron domains on an atom, then the atom is s p 2 hybridized. s p 2 orbitals are formed by mixing of one s and two p . If there are four electron domains on an atom, then the atom is s p 3 hybridized. s p 3 orbitals are formed by mixing of one s and three p . A single bond has a sigma bond. A double bond contains a sigma bond and a pi bond. A triple bond contains a sigma bond and two pi bonds.
Solution Summary: The author explains the molecular formula of the given compound and the geometry of each carbon and oxygen atom.
Interpretation: The molecular formula of the given compound is to be written. The hybridization of each carbon and oxygen atom is to be determined. The geometry of each carbon and oxygen atom is to be described.
Concept introduction:
Mixing of atomic orbitals to form degenerate molecular orbitals is called hybridization.
Hybridization state of each atom is to be calculated from the total number of sigma bond pairs and lone pairs of that atom.
If there are two electron domains on an atom, then the atom is sp hybridized. sp orbitals are formed by mixing of one s and one p.
If there are three electron domains on an atom, then the atom is sp2 hybridized. sp2 orbitals are formed by mixing of one s and two p.
If there are four electron domains on an atom, then the atom is sp3 hybridized. sp3 orbitals are formed by mixing of one s and three p.
A single bond has a sigma bond.
A double bond contains a sigma bond and a pi bond.
A triple bond contains a sigma bond and two pi bonds.
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Write the balanced molecular chemical equation for the reaction in aqueous solution for
mercury(I) nitrate and chromium(VI) sulfate. If no reaction occurs, simply write only NR. Be
sure to include the proper phases for all species within the reaction.
3 Hg(NO3)2(aq) + Cг2(SO4)3(aq) → 3 Hg₂SO (s) + 2 Cr(NO3), (aq)
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Deducing the reactants of a Diels-Alder reaction
n the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one
step, by moderately heating the reactants?
?
Δ
• If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any
arrangement you like.
• If your answer is no, check the box under the drawing area instead.
Explanation Check
Click and drag to start drawing a structure.
>
Predict the major products of the following organic reaction:
+
Some important notes:
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• Draw the major product, or products, of the reaction in the drawing area below.
• If there aren't any products, because no reaction will take place, check the box below the drawing area instead.
• Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are
enantiomers.
Explanation
Check
Click and drag to start drawing a structure.
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Quantum Molecular Orbital Theory (PChem Lecture: LCAO and gerade ungerade orbitals); Author: Prof Melko;https://www.youtube.com/watch?v=l59CGEstSGU;License: Standard YouTube License, CC-BY