The approximate value of the indicated bond angle is to be indicated. Concept introduction: To determine the geometry, first draw a Lewis structure of the molecule. Count the number of electron pairs or domains around the central atom. Electron domain is the bond, and lone pair of electrons are placed around the central atom. Electron domain is the bond and lone pair of electrons around the central atom. According to VSEPR, the electron domains repel each other, and arrange themselves as far apart as possible space. Molecular geometry is the spatial arrangement of bonded atoms. If no lone pairs are present, then molecular geometry is identical to the electron domain geometry. The lone pair–lone pair repulsion is greater than a lone pair–bond pair repulsion, which in turn is greater than bond pair–bond pair repulsion. To draw a Lewis structure, first, the sum of the valence electrons of all the atoms is determined. In case of a polyatomic ion, electrons are added if there is negative charge, and subtracted if there is a positive charge on the ion. A skeleton structure is drawn connecting all the atoms and each bond contains two electrons. Then, the electrons are placed on the terminal atoms as lone pairs, to complete their octet. Remaining electrons are placed on central atom as lone pairs. If there are no valence electrons to complete the octet of the central atom, then one or more terminal atoms share a lone pair to form a double bond.

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Answer 1

Question

Chapter 9.1, Problem 3CP

Interpretation Introduction

Interpretation:

The approximate value of the indicated bond angle is to be indicated.

Concept introduction:

To determine the geometry, first draw a Lewis structure of the molecule.

Count the number of electron pairs or domains around the central atom. Electron domain is the bond, and lone pair of electrons are placed around the central atom.

Electron domain is the bond and lone pair of electrons around the central atom.

According to VSEPR, the electron domains repel each other, and arrange themselves as far apart as possible space.

Molecular geometry is the spatial arrangement of bonded atoms. If no lone pairs are present, then molecular geometry is identical to the electron domain geometry.

The lone pair–lone pair repulsion is greater than a lone pair–bond pair repulsion, which in turn is greater than bond pair–bond pair repulsion.

To draw a Lewis structure, first, the sum of the valence electrons of all the atoms is determined. In case of a polyatomic ion, electrons are added if there is negative charge, and subtracted if there is a positive charge on the ion.

A skeleton structure is drawn connecting all the atoms and each bond contains two electrons.

Then, the electrons are placed on the terminal atoms as lone pairs, to complete their octet.

Remaining electrons are placed on central atom as lone pairs.

If there are no valence electrons to complete the octet of the central atom, then one or more terminal atoms share a lone pair to form a double bond.

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Answer 2

Question

Chapter 9.1, Problem 3CP

Interpretation Introduction

Interpretation:

The approximate value of the indicated bond angle is to be indicated.

Concept introduction:

To determine the geometry, first draw a Lewis structure of the molecule.

Count the number of electron pairs or domains around the central atom. Electron domain is the bond, and lone pair of electrons are placed around the central atom.

Electron domain is the bond and lone pair of electrons around the central atom.

According to VSEPR, the electron domains repel each other, and arrange themselves as far apart as possible space.

Molecular geometry is the spatial arrangement of bonded atoms. If no lone pairs are present, then molecular geometry is identical to the electron domain geometry.

The lone pair–lone pair repulsion is greater than a lone pair–bond pair repulsion, which in turn is greater than bond pair–bond pair repulsion.

To draw a Lewis structure, first, the sum of the valence electrons of all the atoms is determined. In case of a polyatomic ion, electrons are added if there is negative charge, and subtracted if there is a positive charge on the ion.

A skeleton structure is drawn connecting all the atoms and each bond contains two electrons.

Then, the electrons are placed on the terminal atoms as lone pairs, to complete their octet.

Remaining electrons are placed on central atom as lone pairs.

If there are no valence electrons to complete the octet of the central atom, then one or more terminal atoms share a lone pair to form a double bond.

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Answer 3

Question

Chapter 9.1, Problem 3CP

Interpretation Introduction

Interpretation:

The approximate value of the indicated bond angle is to be indicated.

Concept introduction:

To determine the geometry, first draw a Lewis structure of the molecule.

Count the number of electron pairs or domains around the central atom. Electron domain is the bond, and lone pair of electrons are placed around the central atom.

Electron domain is the bond and lone pair of electrons around the central atom.

According to VSEPR, the electron domains repel each other, and arrange themselves as far apart as possible space.

Molecular geometry is the spatial arrangement of bonded atoms. If no lone pairs are present, then molecular geometry is identical to the electron domain geometry.

The lone pair–lone pair repulsion is greater than a lone pair–bond pair repulsion, which in turn is greater than bond pair–bond pair repulsion.

To draw a Lewis structure, first, the sum of the valence electrons of all the atoms is determined. In case of a polyatomic ion, electrons are added if there is negative charge, and subtracted if there is a positive charge on the ion.

A skeleton structure is drawn connecting all the atoms and each bond contains two electrons.

Then, the electrons are placed on the terminal atoms as lone pairs, to complete their octet.

Remaining electrons are placed on central atom as lone pairs.

If there are no valence electrons to complete the octet of the central atom, then one or more terminal atoms share a lone pair to form a double bond.

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Answer 4

Question

Chapter 9.1, Problem 3CP

Interpretation Introduction

Interpretation:

The approximate value of the indicated bond angle is to be indicated.

Concept introduction:

To determine the geometry, first draw a Lewis structure of the molecule.

Count the number of electron pairs or domains around the central atom. Electron domain is the bond, and lone pair of electrons are placed around the central atom.

Electron domain is the bond and lone pair of electrons around the central atom.

According to VSEPR, the electron domains repel each other, and arrange themselves as far apart as possible space.

Molecular geometry is the spatial arrangement of bonded atoms. If no lone pairs are present, then molecular geometry is identical to the electron domain geometry.

The lone pair–lone pair repulsion is greater than a lone pair–bond pair repulsion, which in turn is greater than bond pair–bond pair repulsion.

To draw a Lewis structure, first, the sum of the valence electrons of all the atoms is determined. In case of a polyatomic ion, electrons are added if there is negative charge, and subtracted if there is a positive charge on the ion.

A skeleton structure is drawn connecting all the atoms and each bond contains two electrons.

Then, the electrons are placed on the terminal atoms as lone pairs, to complete their octet.

Remaining electrons are placed on central atom as lone pairs.

If there are no valence electrons to complete the octet of the central atom, then one or more terminal atoms share a lone pair to form a double bond.

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Answer 5

Chapter 9.1, Problem 3CP

Interpretation Introduction

Interpretation:

The approximate value of the indicated bond angle is to be indicated.

Concept introduction:

To determine the geometry, first draw a Lewis structure of the molecule.

Count the number of electron pairs or domains around the central atom. Electron domain is the bond, and lone pair of electrons are placed around the central atom.

Electron domain is the bond and lone pair of electrons around the central atom.

According to VSEPR, the electron domains repel each other, and arrange themselves as far apart as possible space.

Molecular geometry is the spatial arrangement of bonded atoms. If no lone pairs are present, then molecular geometry is identical to the electron domain geometry.

The lone pair–lone pair repulsion is greater than a lone pair–bond pair repulsion, which in turn is greater than bond pair–bond pair repulsion.

To draw a Lewis structure, first, the sum of the valence electrons of all the atoms is determined. In case of a polyatomic ion, electrons are added if there is negative charge, and subtracted if there is a positive charge on the ion.

A skeleton structure is drawn connecting all the atoms and each bond contains two electrons.

Then, the electrons are placed on the terminal atoms as lone pairs, to complete their octet.

Remaining electrons are placed on central atom as lone pairs.

If there are no valence electrons to complete the octet of the central atom, then one or more terminal atoms share a lone pair to form a double bond.

Answer 6

Chapter 9.1, Problem 3CP

Interpretation Introduction

Interpretation:

The approximate value of the indicated bond angle is to be indicated.

Concept introduction:

To determine the geometry, first draw a Lewis structure of the molecule.

Count the number of electron pairs or domains around the central atom. Electron domain is the bond, and lone pair of electrons are placed around the central atom.

Electron domain is the bond and lone pair of electrons around the central atom.

According to VSEPR, the electron domains repel each other, and arrange themselves as far apart as possible space.

Molecular geometry is the spatial arrangement of bonded atoms. If no lone pairs are present, then molecular geometry is identical to the electron domain geometry.

The lone pair–lone pair repulsion is greater than a lone pair–bond pair repulsion, which in turn is greater than bond pair–bond pair repulsion.

To draw a Lewis structure, first, the sum of the valence electrons of all the atoms is determined. In case of a polyatomic ion, electrons are added if there is negative charge, and subtracted if there is a positive charge on the ion.

A skeleton structure is drawn connecting all the atoms and each bond contains two electrons.

Then, the electrons are placed on the terminal atoms as lone pairs, to complete their octet.

Remaining electrons are placed on central atom as lone pairs.

If there are no valence electrons to complete the octet of the central atom, then one or more terminal atoms share a lone pair to form a double bond.

Answer 7

Chapter 9.1, Problem 3CP

Interpretation Introduction

Interpretation:

The approximate value of the indicated bond angle is to be indicated.

Concept introduction:

To determine the geometry, first draw a Lewis structure of the molecule.

Count the number of electron pairs or domains around the central atom. Electron domain is the bond, and lone pair of electrons are placed around the central atom.

Electron domain is the bond and lone pair of electrons around the central atom.

According to VSEPR, the electron domains repel each other, and arrange themselves as far apart as possible space.

Molecular geometry is the spatial arrangement of bonded atoms. If no lone pairs are present, then molecular geometry is identical to the electron domain geometry.

The lone pair–lone pair repulsion is greater than a lone pair–bond pair repulsion, which in turn is greater than bond pair–bond pair repulsion.

To draw a Lewis structure, first, the sum of the valence electrons of all the atoms is determined. In case of a polyatomic ion, electrons are added if there is negative charge, and subtracted if there is a positive charge on the ion.

A skeleton structure is drawn connecting all the atoms and each bond contains two electrons.

Then, the electrons are placed on the terminal atoms as lone pairs, to complete their octet.

Remaining electrons are placed on central atom as lone pairs.

If there are no valence electrons to complete the octet of the central atom, then one or more terminal atoms share a lone pair to form a double bond.

Answer 8

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Answer 9

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Answer 11

Ch. 9.1 - Practice Problem ATTEMPT Determine the shapes of...Ch. 9.1 - Prob. 1PPB Ch. 9.1 - Prob. 1PPC Ch. 9.1 - 9.1.1 What are the electron-domain geometry and...Ch. 9.1 - What are the electron-domain geometry and...Ch. 9.1 - Prob. 3CP Ch. 9.1 - Prob. 4CP Ch. 9.1 - Prob. 5CP Ch. 9.2 - Practice Problem ATTEMPT Ethanolamine has a...Ch. 9.2 - Practice Problem BUILD The bond angle in is...

Solution Summary: The author explains how electron domains repel each other and arrange themselves as far apart as possible space.

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Chapter 9 Solutions