Chemistry
4th Edition
ISBN: 9780078021527
Author: Julia Burdge
Publisher: McGraw-Hill Education
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 9, Problem 78AP
Interpretation Introduction
Interpretation:
The hybridization state of As in
Concept Introduction:
Hybridization is based on the formation of hybrid orbitals by mixing of atomic orbitals.
To determine hybridization of an atom, the Lewis structure of the molecule is drawn.
The number of electron domains present around atoms are determined to predict the number of hybrid orbitals used for bonding.
When atomic orbitals combine, they form equal number of hybrid orbitals.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Draw the product of the following Sharpless epoxidation, including stereochemistry. Click the "draw
structure" button to launch the drawing utility.
-OH
(CH3)3C-OOH
Ti[OCH(CH3)2]4
(+)-DET
draw structure ...
Guid
What alkyne (or diyne) yields the following oxidative cleavage products? Click the "draw structure"
button to launch the drawing utility.
draw structure ...
CO₂ +
OH
lighting discharges in the atmosphere catalyze the conversion of nitrogen to nitric oxide. How many grams of nitrogen would be required to make 25.0 g of nitric oxide in this way ?
Chapter 9 Solutions
Chemistry
Ch. 9.1 - Practice Problem ATTEMPT
Determine the shapes of...Ch. 9.1 - Prob. 1PPBCh. 9.1 - Prob. 1PPCCh. 9.1 - 9.1.1 What are the electron-domain geometry and...Ch. 9.1 - What are the electron-domain geometry and...Ch. 9.1 - Prob. 3CPCh. 9.1 - Prob. 4CPCh. 9.1 - Prob. 5CPCh. 9.2 - Practice Problem ATTEMPT
Ethanolamine has a...Ch. 9.2 - Practice Problem BUILD
The bond angle in is...
Ch. 9.2 - Practice ProblemCONCEPTUALIZE Which of these...Ch. 9.2 - 9.2.1 Identify the polar molecules in the...Ch. 9.2 - Identify the nonpolar molecules in the following...Ch. 9.3 - Practice ProblemATTEMPT Use valence bond theory to...Ch. 9.3 - Practice ProblemBUILD For which molecule(s) can we...Ch. 9.3 - Practice ProblemCONCEPTUALIZE Which of these...Ch. 9.3 - Which of the following atoms, in its ground state,...Ch. 9.3 - According to valence bond theory, how many bonds...Ch. 9.4 - Practice Problem ATTEMPT Use hybrid orbital theory...Ch. 9.4 - Practice ProblemBUILD Use hybrid orbital theory to...Ch. 9.4 - Prob. 1PPCCh. 9.4 - How many orbitals does a set of s p 2 hybrid...Ch. 9.4 - How many p atomic orbitals are required to...Ch. 9.5 - Practice Problem ATTEMPT
The active ingredient in...Ch. 9.5 - Practice ProblemBUILD Determine the total number...Ch. 9.5 - Practice ProblemCONCEPTUALIZE In terms of valence...Ch. 9.5 - Which of the following molecules contain one or...Ch. 9.5 - 9.5.2 From left to right, give the hybridization...Ch. 9.5 - Which of the following pairs of atomic orbitals on...Ch. 9.5 - 9.5.4 Which of the following pairs of atomic...Ch. 9.6 - Practice ProblemATTEMPT Use valence bond theory...Ch. 9.6 - Prob. 1PPBCh. 9.6 - Prob. 1PPCCh. 9.6 - Prob. 1CPCh. 9.6 - Prob. 2CPCh. 9.6 - Prob. 3CPCh. 9.6 - Prob. 4CPCh. 9.7 - Prob. 1PPACh. 9.7 - Prob. 1PPBCh. 9.7 - Prob. 1PPCCh. 9.7 - Prob. 1CPCh. 9.7 - Prob. 2CPCh. 9.7 - Prob. 3CPCh. 9.7 - Prob. 4CPCh. 9.8 - Practice ProblemATTEMPT Use a combination of...Ch. 9.8 - Practice ProblemBUILD Use a combination of valence...Ch. 9.8 - Prob. 1PPCCh. 9 - Prob. 1KSPCh. 9 - Which of the following species does not have...Ch. 9 - 9.3
Which of the following species is polar?
Ch. 9 - Which of the following species is nonpolar (a) IC1...Ch. 9 - How is the geometry of a molecule defined, and why...Ch. 9 - 9.2 Sketch the shape of a linear triatomic...Ch. 9 - How many atoms are directly bonded to the central...Ch. 9 - Discuss the basic features of the VSEPR model....Ch. 9 - In the trigonal bipyramidal arrangement, why does...Ch. 9 - 9.6 Explain why the molecule is not square...Ch. 9 - Predict the geometries of the following species...Ch. 9 - Predict the geometries of the following species: (...Ch. 9 - Predict the geometry of the following molecules...Ch. 9 - Predict the geometry of the following molecules...Ch. 9 - Predict the geometry of the following ions using...Ch. 9 - 9.12 Predict the geometries of the following ions:...Ch. 9 - Describe the geometry around each of the three...Ch. 9 - 9.14 Which of the following species are...Ch. 9 - Prob. 15QPCh. 9 - The bonds in beryllium hydride ( BeH 2 ) molecules...Ch. 9 - Determine whether (a) BrF 5 and (b) BCl 3 are...Ch. 9 - Determine whether (a) OCS and (b) XeF 4 are polar.Ch. 9 - Prob. 19QPCh. 9 - Prob. 20QPCh. 9 - Prob. 21QPCh. 9 - Use valence bond theory to explain the bonding in...Ch. 9 - Prob. 23QPCh. 9 - Prob. 24QPCh. 9 - 9.25 What is the hybridization of atomic orbitals?...Ch. 9 - Prob. 26QPCh. 9 - 9.27 What is the angle between the following two...Ch. 9 - Prob. 28QPCh. 9 - Prob. 29QPCh. 9 - Prob. 30QPCh. 9 - Prob. 31QPCh. 9 - Prob. 32QPCh. 9 - Prob. 33QPCh. 9 - Prob. 34QPCh. 9 - Which of the following pairs of atomic orbitals of...Ch. 9 - Prob. 36QPCh. 9 - 9.37 Specify which hybrid orbitals are used by...Ch. 9 - The allene molecule ( H 2 C=C=CH 2 ) is linear...Ch. 9 - Prob. 39QPCh. 9 - Prob. 40QPCh. 9 - How many pi bonds and sigma bonds are there in the...Ch. 9 - Prob. 42QPCh. 9 - Benzo(a)pyrene is a potent carcinogen found in...Ch. 9 - What is molecular orbital theory? How does it...Ch. 9 - 9.45 Define the following terms: bonding molecular...Ch. 9 - Sketch the shapes of the following molecular...Ch. 9 - Explain the significance of bond order. Can bond...Ch. 9 - Explain in molecular orbital terms the changes in...Ch. 9 - 9.49 The formation of from two atoms is an...Ch. 9 - 9.50 Draw a molecular orbital energy level diagram...Ch. 9 - Prob. 51QPCh. 9 - Prob. 52QPCh. 9 - Which of these species has a longer bond, B 2 or B...Ch. 9 - Prob. 54QPCh. 9 - 9.55 Compare the Lewis and molecular orbital...Ch. 9 - Prob. 56QPCh. 9 - Prob. 57QPCh. 9 - Prob. 58QPCh. 9 - A single bond is almost always a sigma bond, and a...Ch. 9 - Prob. 60QPCh. 9 - In Chapter 8, we saw that the resonance concept is...Ch. 9 - Prob. 62QPCh. 9 - Prob. 63QPCh. 9 - Prob. 64QPCh. 9 - Nitryl fluoride ( FNO 2 ) is very reactive...Ch. 9 - Prob. 66QPCh. 9 - Prob. 67QPCh. 9 - Which of the following species is not likely to...Ch. 9 - Prob. 69APCh. 9 - Although both carbon and silicon are in Group 4A,...Ch. 9 - Predict the geometry of sulfur dichloride ( SCl 2...Ch. 9 - Antimony pentafluoride ( sbF 5 ) reacts with XeF 4...Ch. 9 - Prob. 73APCh. 9 - Prob. 74APCh. 9 - Predict the bond angles for the following...Ch. 9 - Briefly compare the VSEPR and hybridization...Ch. 9 - 9.77 Draw Lewis structures and give the other...Ch. 9 - Prob. 78APCh. 9 - Determine whether (a) PCl 5 and (b) H 2 CO (C...Ch. 9 - Prob. 80APCh. 9 - 9.81 Which of the following molecules are linear:...Ch. 9 - Prob. 82APCh. 9 - 9.83 The molecule can exist in either of the...Ch. 9 - Cyclopropane ( C 3 H 6 ) has the shape of a...Ch. 9 - Determine whether (a) CH 2 Cl 2 and (b) XeF 4 are...Ch. 9 - 9.86 Does the following molecule have a dipole...Ch. 9 - For which molecular geometries (linear, bent,...Ch. 9 - Prob. 88APCh. 9 - 9.89 Carbon suboxide is a colorless...Ch. 9 - The following molecules ( AX 4 Y 2 ) all have an...Ch. 9 - Prob. 91APCh. 9 - Write the ground-state electron configuration for...Ch. 9 - 9.93 What is the hybridization of C and of N in...Ch. 9 - The stable allotropic form of phosphorus is P 4 ,...Ch. 9 - Prob. 95APCh. 9 - Use molecular orbital theory to explain the...Ch. 9 - Carbon dioxide has a linear geometry and is...Ch. 9 - Draw three Lewis structures for compounds with the...Ch. 9 - Prob. 99APCh. 9 - Prob. 100APCh. 9 - Prob. 101APCh. 9 - Draw the Lewis structure of ketene ( C 2 H 2 O )...Ch. 9 - Prob. 103APCh. 9 - Which of the following ions possess a dipole...Ch. 9 - Prob. 105APCh. 9 - Prob. 106APCh. 9 - The compound TCDD, or...Ch. 9 - Progesterone is a hormone responsible for female...Ch. 9 - 9.109 Carbon monoxide is a poisonous compound due...Ch. 9 - Prob. 110APCh. 9 - Prob. 111APCh. 9 - Prob. 112APCh. 9 - 9.113 The compound 1,2-dichloroethane is...Ch. 9 - Consider an N 2 molecule in its first excited...Ch. 9 - Prob. 115APCh. 9 - Prob. 1SEPPCh. 9 - Prob. 2SEPPCh. 9 - These questions are not based on a descriptive...Ch. 9 - These questions are not based on a descriptive...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- The electron of a hydrogen atom is excited to the 4d orbital. Calculate the energy of the emitted photon if the electron were to move to each of the following orbitals: (a) 1s; (b) 2p; (c) 2s; (d) 4s. (e) Suppose the outermost electron of a potassium atom were excited to a 4d orbital and then moved to each of these same orbitals. Describe qualitatively the differences that would be found between the emission spectra of potassium and hydrogen (do not perform calculations). Explain your answer.arrow_forwardImagine a four-dimensional world. In it, atoms would have one s orbital and four p orbitals in a given shell. (a) Describe the shape of the Periodic Table of the first 24 elements. (b) What elements would be the first two noble gases (use the names from our world that correspond to the atomic numbers).arrow_forwardThe electron affinity of thulium was measured by a technique called laser photodetachment electron spectroscopy. In this technique, a gaseous beam of anions of an element is bombarded with photons from a laser. The photons knock electrons off some of the anions, and the energies of the emitted electrons are detected. The incident radiation had a wavelength of 1064 nm, and the emitted electrons had an energy of 0.137 eV. Although the analysis is more complicated, we can obtain an estimate of the electron affinity from the energy difference between the photons and the emitted electrons. What is the electron affinity of thulium in electron volts and in kilojoules per mole?arrow_forward
- Be sure to answer all parts. The following alkyne is treated with 03 followed by H₂O. Part 1: How many different compounds are formed in this process? 1 Part 2 out of 2 Draw the product of the reaction. draw structure ...arrow_forwardMany fireworks use magnesium to burn, which releases a significant amount of energy. The heat released causes the oxide to glow, emitting white light. The color of this light can be changed by including nitrates and chlorides of elements that emit in the visible region of their spectra. One such compound is barium nitrate, which produces a yellow-green light. Excited barium ions generate light with wavelengths of 487 nm, 524 nm, 543 nm, and 578 nm. For each case, calculate: (a) the change in energy (in electron volts) of a barium atom and (b) the molar change in energy (in kilojoules per second).arrow_forwardClouds of hot, luminous interstellar hydrogen gas can be seen in some parts of the galaxy. In some hydrogen atoms, electrons are excited to quantum levels with n = 100 or higher. (a) Calculate the wavelength observed on Earth if the electrons fall from the level with n = 100 to one with n = 2. (b) In what series would this transition be found? (c) Some of these high-energy electrons fall into intermediate states, such as n = 90. Would the wavelengths of a transition from the state with n = 100 to one with n = 90 be longer or shorter than those in the Balmer series? Explain your answer.arrow_forward
- In the spectroscopic technique known as photoelectron spectroscopy (PES), ultraviolet radiation is directed at an atom or molecule. Electrons are ejected from the valence shell and their kinetic energies are measured. Since the energy of the incident ultraviolet photons is known and the kinetic energy of the ejected electron is measured, the ionization energy, I, can be deduced because total energy is conserved. (a) Show that the velocity, v, of the ejected electron and the frequency, n, of the incident radiation are related by hv = I + (1/2)mv^2? (b) Use this relation to calculate the ionization energy of a rubidium atom, knowing that light of wavelength 58.4 nm produces electrons with a velocity of 2,450 km/s Recall that 1 J = 1 kg.m^2/s^2arrow_forwardI) In Millikan's experiment, each droplet observed by the technicians contained an even number of electrons. If they had been unaware of this limitation, how would it have affected their report of an electron's charge?II) Millikan measured the charge of an electron in electrostatic units, esu. The data he collected included the following series of charges found on oil drops: 9.60 X 10^-10 esu, 1.92 X 10^-9 esu; 2.40 X 10^-9 esu; 2.88 X 10^-9 esu; and 4.80 X 10^-9 esu. (a) From this series, find the probable charge of the electron in electrostatic units. (b) Estimate the number of electrons in an oil drop with a charge of 6.72 X 10^-9 esu. The actual charge (in Coulombs) of an electron is 1.602 X 10^-19 C. What is the relationship between esu and Coulombs?arrow_forwardmy ccc edu - Search X Quick Access X D2L Homepage - Spring 2025 x N Netflix X Dimensional Analysis - A x+ pp.aktiv.com Q ☆ X Question 59 of 70 The volume of 1 unit of plasma is 200.0 mL If the recommended dosage for adult patients is 10.0 mL per kg of body mass, how many units are needed for a patient with a body mass of 80.0 kg ? 80.0 kg 10.0 DAL 1 units X X 4.00 units 1 1 Jeg 200.0 DAL L 1 units X 200.0 mL = 4.00 units ADD FACTOR *( ) DELETE ANSWER RESET D 200.0 2.00 1.60 × 10³ 80.0 4.00 0.0400 0.250 10.0 8.00 & mL mL/kg kg units/mL L unit Q Search delete prt sc 111 110 19arrow_forward
- Identify the starting material in the following reaction. Click the "draw structure" button to launch the drawing utility. draw structure ... [1] 0 3 C10H18 [2] CH3SCH3 Harrow_forwardIn an equilibrium mixture of the formation of ammonia from nitrogen and hydrogen, it is found that PNH3 = 0.147 atm, PN2 = 1.41 atm and Pн2 = 6.00 atm. Evaluate Kp and Kc at 500 °C. 2 NH3 (g) N2 (g) + 3 H₂ (g) K₂ = (PN2)(PH2)³ = (1.41) (6.00)³ = 1.41 x 104arrow_forwardWhat alkene or alkyne yields the following products after oxidative cleavage with ozone? Click the "draw structure" button to launch the drawing utility. and two equivalents of CH2=O draw structure ...arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Stoichiometry - Chemistry for Massive Creatures: Crash Course Chemistry #6; Author: Crash Course;https://www.youtube.com/watch?v=UL1jmJaUkaQ;License: Standard YouTube License, CC-BY
Bonding (Ionic, Covalent & Metallic) - GCSE Chemistry; Author: Science Shorts;https://www.youtube.com/watch?v=p9MA6Od-zBA;License: Standard YouTube License, CC-BY
General Chemistry 1A. Lecture 12. Two Theories of Bonding.; Author: UCI Open;https://www.youtube.com/watch?v=dLTlL9Z1bh0;License: CC-BY