The approximate value of the indicated bond angle is to be determined. Concept introduction: To determine the geometry, first draw a Lewis structure of the molecule. Count the number of electron pairs or domains around the central atom. Electron domain is the bond, and lone pair of electrons are placed around the central atom. Electron domains are the bond and lone pair of electrons around the central atom. According to VSEPR, the electron domains repel each other, and arrange themselves as far apart as possible in space. Molecular geometry is the spatial arrangement of bonded atoms. If no lone pairs are present, then molecular geometry is identical to the electron domain geometry. The repulsion factor working between lone pair and lone pair is greater as compared to the lone pair–bond pair repulsion, which is further greater than the bond pair–bond pair repulsion. To draw a Lewis structure, first, the sum of the valence electrons of all the atoms is determined. In case of a polyatomic ion, electrons are added if there is negative charge, and subtracted if there is a positive charge on the ion. A skeleton structure is drawn connecting all the atoms and each bond contains two electrons. Then, the electrons are placed on the terminal atoms as lone pairs, to complete their octet. Remaining electrons are placed on central atom as lone pairs. If there are no valence electrons to complete the octet of the central atom, then one or more terminal atoms share a lone pair to form a double bond.

Question

Want to see the full answer?

Answer 1

Question

Chapter 9.1, Problem 4CP

Interpretation Introduction

Interpretation:

The approximate value of the indicated bond angle is to be determined.

Concept introduction:

To determine the geometry, first draw a Lewis structure of the molecule.

Count the number of electron pairs or domains around the central atom. Electron domain is the bond, and lone pair of electrons are placed around the central atom.

Electron domains are the bond and lone pair of electrons around the central atom.

According to VSEPR, the electron domains repel each other, and arrange themselves as far apart as possible in space.

Molecular geometry is the spatial arrangement of bonded atoms. If no lone pairs are present, then molecular geometry is identical to the electron domain geometry.

The repulsion factor working between lone pair and lone pair is greater as compared to the lone pair–bond pair repulsion, which is further greater than the bond pair–bond pair repulsion.

To draw a Lewis structure, first, the sum of the valence electrons of all the atoms is determined. In case of a polyatomic ion, electrons are added if there is negative charge, and subtracted if there is a positive charge on the ion.

A skeleton structure is drawn connecting all the atoms and each bond contains two electrons.

Then, the electrons are placed on the terminal atoms as lone pairs, to complete their octet.

Remaining electrons are placed on central atom as lone pairs.

If there are no valence electrons to complete the octet of the central atom, then one or more terminal atoms share a lone pair to form a double bond.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

3. Assign absolute configuration (Rors) to each chirality center. a. H Nitz C. он b. 0 H-C. C H 7 C. ་-4 917-417 refs H 1つ ८ ડુ d. Но f. -2- 01 Ho -OH 2HN

How many signals do you expect in the H NMR spectrum for this molecule? Br Br Write the answer below. Also, in each of the drawing areas below is a copy of the molecule, with Hs shown. In each copy, one of the H atoms is colored red. Highlight in red all other H atoms that would contribute to the same signal as the H already highlighted red. Note for advanced students: In this question, any multiplet is counted as one signal. Number of signals in the 'H NMR spectrum. For the molecule in the top drawing area, highlight in red any other H atoms that will contribute to the same signal as the H atom already highlighted red. If no other H atoms will contribute, check the box at right. No additional Hs to color in top molecule For the molecule in the bottom drawing area, highlight in red any other H atoms that will contribute to the same signal as the H atom already highlighted red. If no other H atoms will contribute, check the box at right. No additional Hs to color in bottom molecule

In the drawing area below, draw the major products of this organic reaction: 1. NaOH ? 2. CH3Br If there are no major products, because nothing much will happen to the reactant under these reaction conditions, check the box under the drawing area instead. No reaction. Click and drag to start drawing a structure. ☐ : A ค