a) Interpretation: The structure of the product obtained by the hydroboration-oxidation of 2-methyl-2-pentene is to be given. Concept introduction: The hydroboration reaction takes place with syn stereochemistry and results in a non-Markovnikov addition of water to the double bond in an alkene . The resulting product has the hydroxyl group on the less highly substituted carbon. To give: The structure of the product obtained by the hydroboration-oxidation of 2-methyl-2-pentene.

Question

Q1: Answer the questions for the reaction below: ..!! Br OH a) Predict the product(s) of the reaction. b) Is the substrate optically active? Are the product(s) optically active as a mix? c) Draw the curved arrow mechanism for the reaction. d) What happens to the SN1 reaction rate in each of these instances: 1. Change the substrate to Br 'CI 2. Change the substrate to 3. Change the solvent from 100% CH3CH2OH to 10% CH3CH2OH + 90% DMF 4. Increase the substrate concentration by 3-fold.

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Question

Chapter 8.5, Problem 9P

Interpretation Introduction

a)

Interpretation:

The structure of the product obtained by the hydroboration-oxidation of 2-methyl-2-pentene is to be given.

Concept introduction:

The hydroboration reaction takes place with syn stereochemistry and results in a non-Markovnikov addition of water to the double bond in an alkene. The resulting product has the hydroxyl group on the less highly substituted carbon.

To give:

The structure of the product obtained by the hydroboration-oxidation of 2-methyl-2-pentene.

Interpretation Introduction

b)

Interpretation:

The structure of the product obtained by the hydroboration-oxidation of the compound is to be given.

Concept introduction:

The hydroboration reaction takes place with syn stereochemistry and results in a non-Markovnikov addition of water to the double bond in the alkene. The resulting product has the hydroxyl group on the less highly substituted carbon.

To give:

The structure of the product obtained by the hydroboration-oxidation of the compound shown.

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Q1: Answer the questions for the reaction below: ..!! Br OH a) Predict the product(s) of the reaction. b) Is the substrate optically active? Are the product(s) optically active as a mix? c) Draw the curved arrow mechanism for the reaction. d) What happens to the SN1 reaction rate in each of these instances: 1. Change the substrate to Br 'CI 2. Change the substrate to 3. Change the solvent from 100% CH3CH2OH to 10% CH3CH2OH + 90% DMF 4. Increase the substrate concentration by 3-fold.

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