
Concept explainers
Interpretation:
Given that, when an unsymmetrical alkene such as propene is treated with NBS in aqueous dimethyl sulfoxide, the major product has the bromine atom bonded to the less highly substituted carbon atom. Whether the orientation is Markovnikov or non-Markovnikov is to be explained.
Concept introduction:
NBS can be used as a source of bromine, as it is stable, easily handled compound that slowly decompose in aqueous dimethyl sulfoxide to yield bromine at controlled rate. Bromine from NBS adds on to the double bond to give a cyclic bromonium ion. Water, being a nucleophile, attacks the bromonium ion from the unshielded side to give an intermediate which loses a proton to yield a bromohydrin as the product. The addition occurs with anti stereochemistry.
According to Markovnikov rule, in the addition of HX to unsymmetrical
To explain:
Whether the orientation of groups in the addition reaction between propene and NBS in aqueous dimethyl sulfoxide ,where in the major product has the bromine atom bonded to the less highly substituted carbon atom, is Markovnikov or non-Markovnikov.

Trending nowThis is a popular solution!

Chapter 8 Solutions
Study Guide with Student Solutions Manual for McMurry's Organic Chemistry, 9th
- Draw the major product of this reaction. Ignore inorganic byproducts. Assume that the water side product is continuously removed to drive the reaction toward products. (CH3)2NH, TSOH Drawingarrow_forwardSo, the first image is what I'm trying to understand regarding my approach. The second image illustrates my teacher's method, and the third image includes my notes on the concepts behind these types of problems.arrow_forwardHAND DRAWarrow_forward
- Draw a mental model for calcium chloride mixed with sodium phosphatearrow_forwardhere is my question (problem number 20) please explain to me thanks!arrow_forwardThe bromination of anisole is an extremely fast reaction. Complete the resonance structures of the intermediate arenium cation for the reaction (Part 1), and then answer the question that follows (Part 2).arrow_forward
- Drawing of 3-fluro-2methylphenolarrow_forwardWhich compound(s) will be fully deprotonated (>99%) by reaction with one molar equivalent of sodium hydroxide? I, II, III I, || I, III I only II, III SH | H3C-C=C-H || III NH2arrow_forwardWill NBS (and heat or light) work for this reaction, or do we have to use Br2?arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage LearningOrganic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning


