a) Cyclopentene and cyclopentane Interpretation: A simple chemical test to distinguish between cyclopentene and cyclopentane is to be given. How to perform the test and observations made in the test are also to be stated. Concept introduction: Alkenes decolorize bromine as they react with it to yield dibromoderivatives. Alkanes will not decolorize bromine as they do not react with bromine. To give: A simple chemical test to distinguish between cyclopentene and cyclopentane. Further to state how to perform the test and to explain the observations.

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need help please and thanks dont understand only need help with C-F Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7). Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%. Part B - Compare difference in free energy to the thermal…

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Chapter 8.SE, Problem 66AP

Interpretation Introduction

a) Cyclopentene and cyclopentane

Interpretation:

A simple chemical test to distinguish between cyclopentene and cyclopentane is to be given. How to perform the test and observations made in the test are also to be stated.

Concept introduction:

Alkenes decolorize bromine as they react with it to yield dibromoderivatives. Alkanes will not decolorize bromine as they do not react with bromine.

To give:

A simple chemical test to distinguish between cyclopentene and cyclopentane. Further to state how to perform the test and to explain the observations.

Interpretation Introduction

b) 2-Hexene and benzene

Interpretation:

A simple chemical test to distinguish between 2-hexene and benzene is to be given. How to perform the test and observations made in the test are also to be stated.

Concept introduction:

Alkenes decolorize bromine as they react with bromine to give dibromoderivatives. Aromatic compounds will not decolorize bromine water as they do not react with bromine under normal conditions.

To give:

A simple chemical test to distinguish between 2-hexene and benzene. Further to state how to perform the test and to explain the observations.

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need help please and thanks dont understand only need help with C-F Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7). Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%. Part B - Compare difference in free energy to the thermal…

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need help please and thanks dont understand a-b Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7). Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%. Part B - Compare difference in free energy to the thermal energy Divide the…