Chapter 8.5, Problem 36PPS

To determine

To factor: The polynomial $18r^3{t}^2+12r^2{t}^2-6r^{2}t$

Answer to Problem 36PPS

  $6r^{2}t\left(3rt+2t-1\right)$

Explanation of Solution

Given:

  $18r^3{t}^2+12r^2{t}^2-6r^{2}t$

Calculation:

The given polynomial is $18r^3{t}^2+12r^2{t}^2-6r^{2}t$

Factor out the GCF

  $\begin{array}{l}18r^3{t}^2+12r^2{t}^2-6r^{2}t\\ =6r^{2}t\left(3rt+2t-1\right)\end{array}$

So, the factored form is $6r^{2}t\left(3rt+2t-1\right)$