Chapter 8, Problem 25MCQ

To determine

To find the product of given two polynomials.

Answer to Problem 25MCQ

  $-3k^3+4k^2-k$

Explanation of Solution

Given:

  $\left(k-1\right)\left(k-3k^2\right)$

Formula used:

Distributive Law:

  $x\left(y\pm z\right)=x\cdot y\pm x\cdot z$

Calculation:

Consider the given expression,

  $\Rightarrow \left(k-1\right)\left(k-3k^2\right)$

  $\Rightarrow k\cdot k+k\cdot \left(-3k^2\right)-1\cdot k-1\cdot \left(-3k^2\right)$  [ $\because$$x\left(y\pm z\right)=x\cdot y\pm x\cdot z$ ]

  $\begin{array}{l}\Rightarrow k^2-3k^3-k+3k^2\\ \Rightarrow -3k^3+k^2+3k^2-k\\ \Rightarrow -3k^3+4k^2-k\end{array}$

Conclusion:

Therefore, product of the given polynomials is $-3k^3+4k^2-k$ .