Chapter 8.2, Problem 22PPS

To determine

To find the product.

Answer to Problem 22PPS

  $8t^5{u}^3-40t^4{u}^5+8t^{3}u$

Explanation of Solution

Given:

  $4t^{3}u\left(2t^2{u}^2-10t{u}^4+2\right)$

Calculation:

Solving the given expression,

  $\Rightarrow 4t^{3}u\left(2t^2{u}^2-10t{u}^4+2\right)$

  $\Rightarrow 4t^{3}u\cdot 2t^2{u}^2+4t^{3}u\cdot \left(-10t{u}^4\right)+4t^{3}u\cdot 2$

  $\Rightarrow 8t^5{u}^3-40t^4{u}^5+8t^{3}u$

Conclusion:

Therefore, the product is $8t^5{u}^3-40t^4{u}^5+8t^{3}u$ .