Chapter 8.5, Problem 23PPS

To determine

To factor: The polynomial $hj-2h+5j-10$

Answer to Problem 23PPS

  $\left(j-2\right)\left(h+5\right)$

Explanation of Solution

Given:

  $hj-2h+5j-10$

Calculation:

The given polynomial is $hj-2h+5j-10$

Make groups as shown below

  $\left(hj-2h\right)+\left(5j-10\right)$

So, factored out the GCF from each of the group and then factored out the common factor

  $\begin{array}{l}\left(hj-2h\right)+\left(5j-10\right)\\ =h\left(j-2\right)+5\left(j-2\right)\\ =\left(j-2\right)\left(h+5\right)\end{array}$

So, the factored form is $\left(j-2\right)\left(h+5\right)$