Chapter 8.5, Problem 13CYU

a.

To determine

To determine the factored form of the expression for the height of the spider after $t$ seconds.

Answer to Problem 13CYU

  $4t(3-4t)$

Explanation of Solution

Given:

Height of the jumping spider in feet $=12t-16t^2$ , $t$ represents time.

Calculation:

Height of the jumping spider in feet $=12t-16t^2$ , $t$ represents time

  $\Rightarrow h=12t-16t^2$ where $h$ represents the height,

  $\Rightarrow h=4t(3-4t)$

Conclusion:

Therefore, the factored form of the expression for the height of the spider after $t$ seconds is $h=4t(3-4t)$ feet.

b.

To determine

To determine the spider height after $0.1$ second.

Answer to Problem 13CYU

  $h=1.36$

Explanation of Solution

Given:

Height of the jumping spider in feet $=12t-16t^2$ , $t$ represents time

  $t=0.1$ second

Calculation:

Height of the jumping spider in feet $=12t-16t^2$ , $t$ represents time

  $\Rightarrow h=12t-16t^2$ where $h$ represents the height,

Now, given value of $t=0.1$ second,

  $\Rightarrow h=12(0.1)-16{(0.1)}^2$

  $\Rightarrow h=1.36$

Conclusion:

Therefore, the spider height after $0.1$ second is $h=1.36$ feet.

c.

To determine

To determine the spider height after $0.5$ second.

Answer to Problem 13CYU

  $h=2$

Explanation of Solution

Given:

Height of the jumping spider in feet $=12t-16t^2$ , $t$ represents time

  $t=0.5$ second

Calculation:

Height of the jumping spider in feet $=12t-16t^2$ , $t$ represents time

  $\Rightarrow h=12t-16t^2$ where $h$ represents the height,

Now, given value of $t=0.5$ second,

  $\Rightarrow h=12(0.5)-16{(0.5)}^2$

  $\Rightarrow h=2$

Conclusion:

Therefore, the spider height after $0.5$ second is $h=2$ feet.