Chapter 8, Problem 33MCQ

To determine

To find the product of given two polynomials.

Answer to Problem 33MCQ

  $81k^2-1$

Explanation of Solution

Given:

  $\left(9k+1\right)\left(9k-1\right)$

Formula used:

  $\left(a^2-b^2\right)=\left(a-b\right)\left(a+b\right)$

Calculation:

Consider the given expression,

  $\Rightarrow \left(9k+1\right)\left(9k-1\right)$

  $\Rightarrow {\left(9k\right)}^2-{\left(1\right)}^2$  [ $\because$$\left(a^2-b^2\right)=\left(a-b\right)\left(a+b\right)$ ]

  $\Rightarrow 81k^2-1$

Conclusion:

Therefore, product of the given polynomials is $81k^2-1$ .