Chapter 8, Problem 22MCQ

To determine

To find the product of given two polynomials.

Answer to Problem 22MCQ

  $3b^2-14b+8$

Explanation of Solution

Given:

  $\left(3b-2\right)\left(b-4\right)$

Formula used:

Distributive Law:

  $x\left(y\pm z\right)=x\cdot y\pm x\cdot z$

Calculation:

Consider the given expression,

  $\Rightarrow \left(3b-2\right)\left(b-4\right)$

  $\Rightarrow 3b\cdot b+3b\cdot \left(-4\right)-2\cdot b-2\cdot \left(-4\right)$  [ $\because$$x\left(y\pm z\right)=x\cdot y\pm x\cdot z$ ]

  $\begin{array}{l}\Rightarrow 3b^2-12b-2b+8\\ \Rightarrow 3b^2-14b+8\end{array}$

Conclusion:

Therefore, product of the given polynomials is $3b^2-14b+8$ .