Chapter 8.1, Problem 39PPS

To determine

To find: The sum or difference $\left(4a-5b^2+3\right)+\left(6-2a+3b^2\right)$

Answer to Problem 39PPS

  $-2b^2+2a+9$

Explanation of Solution

Given:

  $\left(4a-5b^2+3\right)+\left(6-2a+3b^2\right)$

Calculation:

The given expression is $\left(4a-5b^2+3\right)+\left(6-2a+3b^2\right)$

Remove all the parenthesis

  $4a-5b^2+3+6-2a+3b^2$

Group the like terms

  $-5b^2+3b^2-2a+4a+3+6$

Combine the like terms

  $-2b^2+2a+9$