Concept explainers
a)
Interpretation:
- The rate determining step of the given reaction has to be predicted.
Concept Introduction:
Reactions of conjugated dienes:
An electrophilic addition reaction to a conjugated diene forms both
Kinetic and
Kinetic product: The more rapidly formed product is called the kinetic product. The reactions that produce the kinetic product as the major product are said to be kinetically controlled. The kinetic product predominates when the reaction is irreversible.
Thermodynamic product: The more stable product is called the thermodynamic product. The reactions that produce the thermodynamic product as the major product are said to be thermodynamically controlled. The thermodynamic product predominates when the reaction is reversible.
Rule: The stabilities of carbocation are,
b)
Interpretation:
- The product determining step of the given reaction has to be predicted.
Concept Introduction:
Reactions of conjugated dienes:
An electrophilic addition reaction to a conjugated diene forms both
Kinetic and thermodynamic products:
Kinetic product: The more rapidly formed product is called the kinetic product. The reactions that produce the kinetic product as the major product are said to be kinetically controlled. The kinetic product predominates when the reaction is irreversible.
Thermodynamic product: The more stable product is called the thermodynamic product. The reactions that produce the thermodynamic product as the major product are said to be thermodynamically controlled. The thermodynamic product predominates when the reaction is reversible.
Rule: The stabilities of carbocation are,
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EBK ORGANIC CHEMISTRY
- 1. Alkene Addition Reaction Mechanisms: Draw the product for the addition reactions below in the boxes. Then, draw the FULL electron-pushing mechanism for the reactions, including all intermediates (with formal charges and lone pairs of electrons) and all electron pushing arrows. For each step, label the electrophile and nucleophile and name what type of elementary step it is. a. Addition of H-Br to an alkene: of b. Addition of H₂O using an acid catalyst: H-CI: H-Ö-SO₂H (cat.) H₂Oarrow_forwardA reaction flask contains 2-bromopentane in an ethanolic solution of sodium ethoxide at room temperature and result in the formation of two olefnic products. What is responsible for the formation of major and minor products. A. Different activated complex involved in the mechanism. B. Bimolecular nucleophilic substitution reaction. C. Bimolecular elimination reaction D. The presence of sodium ethoxide. E. The hybridization nature of secondary carbocationarrow_forwardYou have 3 isomers with the chemical formula of C4H9Br .All of them reacted with the same Nu in a SN reaction .arrow_forward
- 4. Identify the diene and dienophile used to make these Diel-Alder products. b. CH3 CN deo & CH3 a. CO₂CH3 CO₂CH3arrow_forward09:19 ull 4G Which factors affect the reaction rate in Diels-Alder reactions? OA. Electron.donating group on the diene and electron withdrawing group on dienophile. O B. Electron donating group on both the diene and the dienophile. OC. Electron withdrawing group on both the diene and the dienophile. O D. Addition of catalyst. Add a caption... > Status (Custom)arrow_forwardAddition of HCl to alkene X forms two alkyl halides Y and Z.a.Label Y and Z as a 1,2-addition product or a 1,4-addition product. b. Label Y and Z as the kinetic or thermodynamic product and explain why. c.Explain why addition of HCl occurs at the indicated C=C (called an exocyclic double bond), rather than the other C=C (called an endocyclic double bond).arrow_forward
- a. Draw an energy diagram for this reaction. be sure to label axes, starting materials, any reactive intermediates and products.b. Draw the transition state of this reaction. If an atom has a positive charge indicate it with sigma+/-.arrow_forwardAs we will learn in Section 15.12, many antioxidants-compounds that prevent unwanted radical oxidation reactions from occurring-are phenols, compounds that contain an OH group bonded directly to a benzene ring. a. Explain why homolysis of the O-H bond in phenol requires considerably less energy than homolysis of the O-H bond in ethanol (362 kJ/mol vs. 438 kJ/mol). b. Why is the C-O bond in phenol shorter than the C-O bond in ethanol? -O-H CH,CH2-0-H phenol ethanolarrow_forwardAs we will learn in Section 13.12, many antioxidants–compounds that prevent unwanted radical oxidation reactions from occurring–are phenols, compounds that contain an OH group bonded directly to a benzene ring. a. Explain why homolysis of the O–H bond in phenol requires considerably less energy than homolysis of the O–H bond in ethanol (362 kJ/mol vs. 438 kJ/mol). b.Why is the C–O bond in phenol shorter than the C–O bond in ethanol?arrow_forward
- Consider the two alkene additions reactions a. What are the major products for each reaction? b. What is the mechanism for each reaction? c. Which reaction would be faster and why? Use words like “transition-state, intermediate and/or reactant/product stability” in your justification. Draw the reaction coordinate diagram for both to assist in your explanation.arrow_forward10. Draw an energy diagram for the addition of HBr to 1-pentene. Let one curve on your diagram show the formation of 1-bromopentane product and another curve on the same diagram show the formation of 2- bromopentane product. Draw and label the positions for all reactants, intermediates, and products. Which curve has the higher-energy carbocation intermediate? Which curve has the higher-energy first transition state?arrow_forwardA terminal alkyne (RC=CH) is exposed to excess HBr. What rule should be followed to determine the placement of the halogen atoms in the product? A. Markovnikov rule O B. Hofmann's rule O C. Zaitzev's rule D. Anti-Markovnikov rulearrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning