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Testing a Difference Other Than Zero Sometimes a researcher is interested in testing a difference in means other than zero. In Exercises 27 and 28, you will test the difference between two means using a null hypothesis of H0: μ1 − μ2 = k, H0: μ1 − μ2 ≥ k, or H0: μ1 − μ2 ≤ k. The standardized test statistic is still
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Elementary Statistics: Picturing the World (7th Edition)
- Population Genetics In the study of population genetics, an important measure of inbreeding is the proportion of homozygous genotypesthat is, instances in which the two alleles carried at a particular site on an individuals chromosomes are both the same. For population in which blood-related individual mate, them is a higher than expected frequency of homozygous individuals. Examples of such populations include endangered or rare species, selectively bred breeds, and isolated populations. in general. the frequency of homozygous children from mating of blood-related parents is greater than that for children from unrelated parents Measured over a large number of generations, the proportion of heterozygous genotypesthat is, nonhomozygous genotypeschanges by a constant factor 1 from generation to generation. The factor 1 is a number between 0 and 1. If 1=0.75, for example then the proportion of heterozygous individuals in the population decreases by 25 in each generation In this case, after 10 generations, the proportion of heterozygous individuals in the population decreases by 94.37, since 0.7510=0.0563, or 5.63. In other words, 94.37 of the population is homozygous. For specific types of matings, the proportion of heterozygous genotypes can be related to that of previous generations and is found from an equation. For mating between siblings 1 can be determined as the largest value of for which 2=12+14. This equation comes from carefully accounting for the genotypes for the present generation the 2 term in terms of those previous two generations represented by for the parents generation and by the constant term of the grandparents generation. a Find both solutions to the quadratic equation above and identify which is 1 use a horizontal span of 1 to 1 in this exercise and the following exercise. b After 5 generations, what proportion of the population will be homozygous? c After 20 generations, what proportion of the population will be homozygous?arrow_forwardState whether the standardized test statistic t indicates that you should reject the null hypothesis. Explain. (a) t= 2.242 (b) t = 0 (c) t= 2.195 (d) t= - 2.254 %3D -2219 (a) For t 2.242, should you reject or fail to reject the null hypothesis? O A. Reject Ho, because t>2.219. O B. Reject Ho, because t 2.219. O D. Fail to reject Ho, because t<2.219.arrow_forwardLife on Other Planets Forty-six percent of people believe that there is life on other planets in the universe. A scientist does not agree with this finding. He surveyed 100 randomly selected individuals and found 40 believed that there is life on other planets. At α=0.01, is there sufficient evidence to conclude that the percentage differs from 46% ? Use the P -value method with tables. :H0 ▼(Choose one) :H1 ▼(Choose one) This hypothesis test is a ▼(Choose one) test. Compute the test value. Always round z score values to two decimal places. z= Find the P -value. Round the answer to four decimal places. P-value (d)Make the decision. (choose one) reject/do not reject the null hypothesis (e)Summarize the results. There is ▼(Choose one) that the percentage of people who believe that there is life on other planets differs from 46% .arrow_forward
- MORE BENEFITS OF EATING ORGANIC Using specific data, we find a significant difference in the proportion of fruit flies surviving after 13 days between those eating organic potatoes and those eating conventional (not organic) potatoes. This exercise asks you to conduct a hypothesis test using additional data. In this case, we are testing Ho: Po = Pc Ha: Po > Pc where p, and pc represent the proportion of fruit flies alive at the end of the given time frame of those eating organic food and those eating conventional food, respectively. Use a 5 % significance level. Effect of Organic Soybeans After 5 Days After 5 days, the proportion of fruit flies eating organic soybeans still alive is 0.89, while the proportion still alive eating conventional soybeans is 0.83. The standard error for the difference in proportions is 0.022. What is the value of the test statistic? Round your answer to two decimal places. Z = What is the p-value? Round your answer to three decimal places. p-value = iarrow_forward9arrow_forwardTest the claim that less than 40% of people in the United States expect Social Security willbe able to pay all the benefits they are entitled to under the current law. Use α = 0.10.Does the decision support the department’s claim. Be sure to interpret the test’s decisionand include your interpretation in the letter to Dr. Bob. Data: 83 Yes37 No49 No27 Yes27 No59 Yes44 Yes46 No25 No30 No72 Yes66 No47 No47 No50 Yes76 Yes51 Yes58 No79 Yes69 Yes66 No35 Yes47 No29 Yes76 No31 Yes40 No61 Yes30 Yes71 No64 No18 Noarrow_forward
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