Chapter 8, Problem 8.92P

Interpretation Introduction

(a)

Interpretation:

The volume of $\text{5 M}$ sucrose solution required to prepare $\text{45 mL}$ of $\text{4 M}$ solution is to be calculated.

Concept introduction:

When a solution is diluted the number of moles of the solute remains constant. Mathematically, this can be expressed as follows:

  $\text{Number of moles}=\text{Molarity}\times \text{Volume}$

This can be rewritten as follows:

  $\text{MV}=\text{constant}$

Thus the dilution formula is given as follows:

  ${\text{M}}_1{\text{V}}_1={\text{M}}_2{\text{V}}_2$

Interpretation Introduction

(b)

Interpretation:

The volume of $\text{5 M}$ sucrose solution required to prepare $\text{150 mL}$ of $\text{0}\text{.5 M}$ solution is to be calculated.

Concept introduction:

When a solution is diluted the number of moles of the solute remains constant. Mathematically, this can be expressed as follows:

  $\text{Number of moles}=\text{Molarity}\times \text{Volume}$

This can be rewritten as follows:

  $\text{MV}=\text{constant}$

Thus the dilution formula is given as follows:

  ${\text{M}}_1{\text{V}}_1={\text{M}}_2{\text{V}}_2$

Interpretation Introduction

(c)

Interpretation:

The volume of $\text{0}\text{.025 M}$ solution required to prepare $\text{1}\text{.2 L}$ of $\text{0}\text{.025 M}$ solution is to be calculated.

Concept introduction:

When a solution is diluted the number of moles of the solute remains constant. Mathematically, this can be expressed as follows:

  $\text{Number of moles}=\text{Molarity}\times \text{Volume}$

This can be rewritten as follows:

  $\text{MV}=\text{constant}$

Thus the dilution formula is given as follows:

  ${\text{M}}_1{\text{V}}_1={\text{M}}_2{\text{V}}_2$

Interpretation Introduction

(d)

Interpretation:

The volume of $\text{5 M}$ sucrose solution required to prepare $\text{750 mL}$ of $\text{1 M}$ solution is to be calculated.

Concept introduction:

When a solution is diluted the number of moles of the solute remains constant. Mathematically, this can be expressed as follows:

  $\text{Number of moles}=\text{Molarity}\times \text{Volume}$

This can be rewritten as follows:

  $\text{MV}=\text{constant}$

Thus the dilution formula is given as follows:

  ${\text{M}}_1{\text{V}}_1={\text{M}}_2{\text{V}}_2$