Chapter 8, Problem 8.73P

Interpretation Introduction

(a)

Interpretation:

The molarity of $\text{KCl}$ solution when $\text{3}\text{.5 mol}$ is present in $1.50\text{ L}$ is to be determined.

Concept introduction:

The formula to calculate molarity is given as follows:

  $\text{Molarity}\left(\text{mol/L}\right)=\frac{\text{number of moles}}{\text{volume}\left(\text{L}\right)}$

Interpretation Introduction

(b)

Interpretation:

The molarity of ${\text{NaNO}}_3$ solution when $\text{0}\text{.44 mol}$ is present in $\text{855 mL}$ aqueous solution is to be determined.

Concept introduction:

The formula to calculate molarity is given as follows:

  $\text{Molarity}\left(\text{mol/L}\right)=\frac{\text{number of moles}}{\text{volume}\left(\text{L}\right)}$

The conversion factor to convert $\text{L}$ to $\text{mL}$ is given as follows:

  $1\text{ L}={\text{10}}^3\text{ mL}$

Interpretation Introduction

(c)

Interpretation:

The molarity of $\text{NaCl}$ solution when $25\text{ g}$ is present in $\text{650 mL}$ aqueous solution is to be calculated.

Concept introduction:

The formula to calculate molarity isgiven as follows:

  $\text{Molarity}\left(\text{mol/L}\right)=\frac{\text{number of moles}}{\text{volume}\left(\text{L}\right)}$

The formula to calculate number of moles is given asfollows:

  $\text{Number of moles}=\frac{\text{given mass}\left(\text{g}\right)}{\text{molar mass}\left(\text{g/mol}\right)}$

Interpretation Introduction

(d)

Interpretation:

The molarity of ${\text{NaHCO}}_3$ solution when $10\text{ g}$ is present in $\text{250 mL}$ aqueous solution is to be calculated.

Concept introduction:

The formula to calculate molarity is given as follows:

  $\text{Molarity}\left(\text{mol/L}\right)=\frac{\text{number of moles}}{\text{volume}\left(\text{L}\right)}$