
Concept explainers
(a)
Interpretation:
The number of electrons gained by oxygen when it combines with a metal to form a compound needs to be determined.
Concept Introduction:
When a non-metal combines with a metal to form a compound, the non-metal gains one or more electron(s) while the metal loses one or more electron(s). The non-metal accepts electron(s) in order to satisfy the octet configuration. The octet configuration of an atom refers to the tendency of the main group elements (metals and non-metals) to have eight electrons in the outermost or valence shell, giving it the same electron configuration as that of a noble gas.
(a)

Answer to Problem 53A
Oxygen will gain two electrons when it combines with a metal to form a compound.
Explanation of Solution
Oxygen occurs in group 16 of the periodic table and has six electrons in its valence shell. Therefore, oxygen needs two electrons in order to have a complete octet. These two electrons are gained from a metal when oxygen combines with the metal to form a compound.
(b)
Interpretation:
The number of electrons gained by fluorine must be determined.
Concept Introduction:
Fluorine is a main group element and therefore, must satisfy the octet rule.
(b)

Answer to Problem 53A
Fluorine gains one electron when it combines with a metal.
Explanation of Solution
Fluorine occurs in the halogen group (group 17) of the periodic table and is one electron short of the nearest noble gas configuration. Therefore, fluorine accepts one electron when it combines with a metal to form a fluoride salt.
(c)
Interpretation:
The number of electrons gained by nitrogen must be determined.
Concept Introduction:Nitrogen is a main group element and forms compounds in accordance with the octet rule.
(c)

Answer to Problem 53A
Nitrogen gains three electrons when it combines with a metal to form a compound.
Explanation of Solution
Nitrogen has 5 electrons in the valence shell and must acquire three electrons in order to have a complete octet. These three electrons are gained from a metal when nitrogen forms a nitride salt with the metals.
(d)
Interpretation:
The number of electrons gained by chlorine must be determined.
Concept Introduction:
Chlorine is a main group element and therefore, must satisfy the octet rule.
(d)

Answer to Problem 53A
Chlorine gains one electron when it combines with a metal.
Explanation of Solution
Chlorine occurs in the halogen group (group 17) of the periodic table and is one electron short of the nearest noble gas configuration. Therefore, chlorine accepts one electron when it combines with a metal to form a chloride salt.
(e)
Interpretation:
The number of electrons gained by sulfur must be determined.
Concept Introduction:
As in the other cases above, sulfur is a main group element and therefore, conforms to the octet rule.
(e)

Answer to Problem 53A
Sulfur gains two electrons when it combines with a metal.
Explanation of Solution
Sulfur is a group 16 element and has 6 electrons in its valence shell. Thus, sulfur is two electrons short of the nearest noble gas configuration. Sulfur accepts two electrons from a metal when it forms a sulfide in order to satisfy the noble gas configuration.
Chapter 8 Solutions
World of Chemistry, 3rd edition
- Draw product A, indicating what type of reaction occurs. NH2 F3C CF3 NH OMe NH2-NH2, ACOH Aarrow_forwardPhotochemical smog is formed in part by the action of light on nitrogen dioxide. The wavelength of radiation absorbed by NO2 in this reaction is 197 nm.(a) Draw the Lewis structure of NO2 and sketch its π molecular orbitals.(b) When 1.56 mJ of energy is absorbed by 3.0 L of air at 20 °C and 0.91 atm, all the NO2 molecules in this sample dissociate by the reaction shown. Assume that each absorbed photon leads to the dissociation (into NO and O) of one NO2 molecule. What is the proportion, in parts per million, of NO2 molecules in this sample? Assume that the sample behaves ideally.arrow_forwardCorrect each molecule in the drawing area below so that it has the skeletal ("line") structure it would have if it were dissolved in a 0.1 M aqueous solution of HCI. If there are no changes to be made, check the No changes box under the drawing area. No changes. HO Explanation Check NH, 2 W O :□ G ©2025 M unter Accessibilityarrow_forward
- An expression for the root mean square velocity, vrms, of a gas was derived. Using Maxwell’s velocity distribution, one can also calculate the mean velocity and the most probable velocity (mp) of a collection of molecules. The equations used for these two quantities are vmean=(8RT/πM)1/2 and vmp=(2RT/M)1/2 These values have a fixed relationship to each other.(a) Arrange these three quantities in order of increasing magnitude.(b) Show that the relative magnitudes are independent of the molar mass of the gas.(c) Use the smallest velocity as a reference for establishing the order of magnitude and determine the relationship between the larger and smaller values.arrow_forwardThe reaction of solid dimethylhydrazine, (CH3)2N2H2, and liquefied dinitrogen tetroxide, N2O4, has been investigated for use as rocket fuel. The reaction produces the gases carbon dioxide (CO2), nitrogen (N2), and water vapor (H2O), which are ejected in the exhaust gases. In a controlled experiment, solid dimethylhydrazine was reacted with excess dinitrogen tetroxide, and the gases were collected in a closed balloon until a pressure of 2.50 atm and a temperature of 400.0 K were reached.(a) What are the partial pressures of CO2, N2, and H2O?(b) When the CO2 is removed by chemical reaction, what are the partial pressures of the remaining gases?arrow_forwardOne liter of chlorine gas at 1 atm and 298 K reacts completely with 1.00 L of nitrogen gas and 2.00 L of oxygen gas at the same temperature and pressure. A single gaseous product is formed, which fills a 2.00 L flask at 1.00 atm and 298 K. Use this information to determine the following characteristics of the product:(a) its empirical formula;(b) its molecular formula;(c) the most favorable Lewis formula based on formal charge arguments (the central atom is N);(d) the shape of the molecule.arrow_forward
- How does the square root mean square velocity of gas molecules vary with temperature? Illustrate this relationship by plotting the square root mean square velocity of N2 molecules as a function of temperature from T=100 K to T=300 K.arrow_forwardDraw product B, indicating what type of reaction occurs. F3C CF3 NH2 Me O .N. + B OMearrow_forwardBenzimidazole E. State its formula. sState the differences in the formula with other benzimidazoles.arrow_forward
- Draw product A, indicating what type of reaction occurs. F3C CN CF3 K2CO3, DMSO, H₂O2 Aarrow_forward19) Which metal is most commonly used in galvanization to protect steel structures from oxidation? Lead a. b. Tin C. Nickel d. Zinc 20) The following molecule is an example of a: R₁ R2- -N-R3 a. Secondary amine b. Secondary amide c. Tertiary amine d. Tertiary amidearrow_forwardpls helparrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





