Chapter 8, Problem 38A

(a)

Interpretation Introduction

Interpretation: The given combustion reaction needs to be balanced.

  ${\text{C}}_{\text{2}}{\text{H}}_{\text{5}}{\text{OH}}_{\text{(l)}}{\text{ + O}}_{\text{2}}{}_{\text{(s) }}\stackrel{}{\to }{\text{ CO}}_{\text{2}}{}_{\text{(g)}}+{\text{H}}_{\text{2}}{\text{O}}_{\text{(g)}}$

Concept Introduction:A chemical reaction can be described as the process of conversion of reactant molecules to product molecules by breaking and making of chemical bonds.

A balance chemical reaction contains same number of atoms at both sides of the chemical reaction.

Answer to Problem 38A

  ${\text{C}}_{\text{2}}{\text{H}}_{\text{5}}{\text{OH}}_{\text{(l)}}{\text{ + 3 O}}_{\text{2}}{}_{\text{(s) }}\stackrel{}{\to }{\text{ 2 CO}}_{\text{2}}{}_{\text{(g)}}+3{\text{H}}_{\text{2}}{\text{O}}_{\text{(g)}}$

Explanation of Solution

In a balance chemical equation, the number of atoms must be same at both sides. To balance a chemical reaction, coefficients must be added with the chemical formula to make it same at both sides.

Reactant	Product
C = 2	C = 1→2
H = 6	H = 2→6
O = 3→7	O = 3→7

Thus the balance chemical equation must be:

  ${\text{C}}_{\text{2}}{\text{H}}_{\text{5}}{\text{OH}}_{\text{(l)}}{\text{ + 3 O}}_{\text{2}}{}_{\text{(s) }}\stackrel{}{\to }{\text{ 2 CO}}_{\text{2}}{}_{\text{(g)}}+3{\text{H}}_{\text{2}}{\text{O}}_{\text{(g)}}$

(b)

Interpretation Introduction

Interpretation: The given combustion reaction needs to be balanced.

  ${\text{C}}_6{\text{H}}_{14}{}_{\text{(l)}}{\text{ + O}}_{\text{2}}{}_{\text{(s) }}\stackrel{}{\to }{\text{ CO}}_{\text{2}}{}_{\text{(g)}}+{\text{H}}_{\text{2}}{\text{O}}_{\text{(g)}}$

Concept Introduction:A chemical reaction can be described as the process of conversion of reactant molecules to product molecules by breaking and making of chemical bonds.

A balance chemical reaction contains same number of atoms at both sides of the chemical reaction.

Answer to Problem 38A

  ${\text{2 C}}_6{\text{H}}_{14}{}_{\text{(l)}}{\text{ + 19 O}}_{\text{2}}{}_{\text{(s) }}\stackrel{}{\to }{\text{ 12 CO}}_{\text{2}}{}_{\text{(g)}}+14{\text{H}}_{\text{2}}{\text{O}}_{\text{(g)}}$

Explanation of Solution

In a balance chemical equation, the number of atoms must be same at both sides. To balance a chemical reaction, coefficients must be added with the chemical formula to make it same at both sides.

Reactant	Product
C = 6→12	C = 1→12
H = 14→28	H = 2→28
O = 2→38	O = 3→38

Thus the balance chemical equation must be:

  ${\text{2 C}}_6{\text{H}}_{14}{}_{\text{(l)}}{\text{ + 19 O}}_{\text{2}}{}_{\text{(s) }}\stackrel{}{\to }{\text{ 12 CO}}_{\text{2}}{}_{\text{(g)}}+14{\text{H}}_{\text{2}}{\text{O}}_{\text{(g)}}$

(b)

Interpretation Introduction

Interpretation: The given combustion reaction needs to be balanced.

  ${\text{C}}_6{\text{H}}_{12}{}_{\text{(l)}}{\text{ + O}}_{\text{2}}{}_{\text{(s) }}\stackrel{}{\to }{\text{ CO}}_{\text{2}}{}_{\text{(g)}}+{\text{H}}_{\text{2}}{\text{O}}_{\text{(g)}}$

Concept Introduction:A chemical reaction can be described as the process of conversion of reactant molecules to product molecules by breaking and making of chemical bonds.

A balance chemical reaction contains same number of atoms at both sides of the chemical reaction.

Answer to Problem 38A

  ${\text{C}}_6{\text{H}}_{12}{}_{\text{(l)}}{\text{ + 9 O}}_{\text{2}}{}_{\text{(s) }}\stackrel{}{\to }{\text{ 6 CO}}_{\text{2}}{}_{\text{(g)}}+6{\text{H}}_{\text{2}}{\text{O}}_{\text{(g)}}$

Explanation of Solution

In a balance chemical equation, the number of atoms must be same at both sides. To balance a chemical reaction, coefficients must be added with the chemical formula to make it same at both sides.

Reactant	Product
C = 6→6	C = 1→6
H = 12	H = 2→12
O = 2→18	O = 3→18

Thus the balance chemical equation must be:

  ${\text{C}}_6{\text{H}}_{12}{}_{\text{(l)}}{\text{ + 9 O}}_{\text{2}}{}_{\text{(s) }}\stackrel{}{\to }{\text{ 6 CO}}_{\text{2}}{}_{\text{(g)}}+6{\text{H}}_{\text{2}}{\text{O}}_{\text{(g)}}$