Chapter 8, Problem 14A

(a)

Interpretation Introduction

Interpretation:

The given chemical equation needs to be balanced by indicating the precipitate formed.

  ${\left({\text{NH}}_{\text{4}}\right)}_{\text{2}}{\text{SO}}_{\text{4}}\left(aq\right)+\text{ Ba}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}\left(aq\right)\to$

Concept Introduction :

In a precipitation reaction, one of the compounds formed is insoluble in water, thus, it gets precipitated out from the solution.

Answer to Problem 14A

  ${\left(N{H}_4\right)}_{2}S{O}_4\left(aq\right)+Ba{\left(N{O}_3\right)}_2\left(aq\right)\to BaS{O}_4\left(s\right)+2N{H}_{4}N{O}_3\left(aq\right)$

Explanation of Solution

Aqueous (NH₄)₂SO₄ and aqueous Ba(NO₃)₂ reacts to form a precipitate of BaSO₄ and NH₄NO₃ solution.

The complete balanced equation for the reaction is:

  ${\left(N{H}_4\right)}_{2}S{O}_4\left(aq\right)+Ba{\left(N{O}_3\right)}_2\left(aq\right)\to BaS{O}_4\left(s\right)+2N{H}_{4}N{O}_3\left(aq\right)$

Thus, BaSO₄ is precipitate.

(b)

Interpretation Introduction

Interpretation:

The given chemical equation needs to be balanced by indicating the precipitate formed.

  ${\text{H}}_{\text{2}}\text{S}\left(aq\right) + {\text{NiSO}}_{\text{4}}\left(aq\right) \to$

Concept Introduction :

In a precipitation reaction, one of the compounds formed is insoluble in water thus, it gets precipitated out from the solution.

Answer to Problem 14A

  ${\text{H}}_{\text{2}}\text{S}\left(aq\right) + {\text{NiSO}}_{\text{4}}\left(aq\right) \to \text{ NiS}\left(s\right) +{\text{ H}}_{\text{2}}{\text{SO}}_{\text{4}}\left(aq\right)$

Explanation of Solution

Aqueous H₂S reacts with aqueous NiSO₄ to form a precipitate of NiS and  H₂SO₄ solution.

The complete balanced equation for the reaction is:

  ${\text{H}}_{\text{2}}\text{S}\left(aq\right) + {\text{NiSO}}_{\text{4}}\left(aq\right) \to \text{ NiS}\left(s\right) +{\text{ H}}_{\text{2}}{\text{SO}}_{\text{4}}\left(aq\right)$

Thus, NiS is precipitate formed in the reaction.

(c)

Interpretation Introduction

Interpretation:

The given chemical equation needs to be balanced by indicating the precipitate formed.

  ${\text{FeCl}}_{\text{3}}\left(aq\right)+3\text{NaOH}\left(aq\right)\to$

Concept Introduction :

In a precipitation reaction, one of the compounds formed is insoluble in water, thus, it gets precipitated out from the solution.

Answer to Problem 14A

  $FeC{l}_3\left(aq\right)+3NaOH\left(aq\right)\to Fe{\left(OH\right)}_3\left(s\right)+3NaCl\left(aq\right)$

Explanation of Solution

Aqueous FeCl₃ and aqueous NaOH reacts to form precipitate of Fe(OH)₃ and NaCl solution

The complete balanced equation for the reaction is:

  $FeC{l}_3\left(aq\right)+3NaOH\left(aq\right)\to Fe{\left(OH\right)}_3\left(s\right)+3NaCl\left(aq\right)$

Thus, Fe(OH)₃ is precipitate formed in the reaction.