The major substitution product that would result from reaction of 2-bromo-2-methylpropane with concentrated aqueous ammonia should be predicted. Concept introduction: Tertiary Haloalkane is a typical example for unimolecuar substitution. It proceeds via two-step mechanism. The first slow step that determines rate is the removal of leaving group from the substrate haloalkane and generates a carbocation. Since the rate is only governed by substrate alone and no other nucleophile or solvent it is termed as unimolecuar substitution. The final step is attack of nucleophile on carbocation generated and formation of racemic products.

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Answer 1

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Chapter 7.4, Problem 7.7TIY

Interpretation Introduction

Interpretation: The major substitution product that would result from reaction of 2-bromo-2-methylpropane with concentrated aqueous ammonia should be predicted.

Concept introduction: Tertiary Haloalkane is a typical example for unimolecuar substitution. It proceeds via two-step mechanism. The first slow step that determines rate is the removal of leaving group from the substrate haloalkane and generates a carbocation. Since the rate is only governed by substrate alone and no other nucleophile or solvent it is termed as unimolecuar substitution. The final step is attack of nucleophile on carbocation generated and formation of racemic products.

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Answer 2

Question

Chapter 7.4, Problem 7.7TIY

Interpretation Introduction

Interpretation: The major substitution product that would result from reaction of 2-bromo-2-methylpropane with concentrated aqueous ammonia should be predicted.

Concept introduction: Tertiary Haloalkane is a typical example for unimolecuar substitution. It proceeds via two-step mechanism. The first slow step that determines rate is the removal of leaving group from the substrate haloalkane and generates a carbocation. Since the rate is only governed by substrate alone and no other nucleophile or solvent it is termed as unimolecuar substitution. The final step is attack of nucleophile on carbocation generated and formation of racemic products.

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Answer 3

Question

Chapter 7.4, Problem 7.7TIY

Interpretation Introduction

Interpretation: The major substitution product that would result from reaction of 2-bromo-2-methylpropane with concentrated aqueous ammonia should be predicted.

Concept introduction: Tertiary Haloalkane is a typical example for unimolecuar substitution. It proceeds via two-step mechanism. The first slow step that determines rate is the removal of leaving group from the substrate haloalkane and generates a carbocation. Since the rate is only governed by substrate alone and no other nucleophile or solvent it is termed as unimolecuar substitution. The final step is attack of nucleophile on carbocation generated and formation of racemic products.

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Answer 4

Question

Chapter 7.4, Problem 7.7TIY

Interpretation Introduction

Interpretation: The major substitution product that would result from reaction of 2-bromo-2-methylpropane with concentrated aqueous ammonia should be predicted.

Concept introduction: Tertiary Haloalkane is a typical example for unimolecuar substitution. It proceeds via two-step mechanism. The first slow step that determines rate is the removal of leaving group from the substrate haloalkane and generates a carbocation. Since the rate is only governed by substrate alone and no other nucleophile or solvent it is termed as unimolecuar substitution. The final step is attack of nucleophile on carbocation generated and formation of racemic products.

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Answer 5

Chapter 7.4, Problem 7.7TIY

Interpretation Introduction

Interpretation: The major substitution product that would result from reaction of 2-bromo-2-methylpropane with concentrated aqueous ammonia should be predicted.

Concept introduction: Tertiary Haloalkane is a typical example for unimolecuar substitution. It proceeds via two-step mechanism. The first slow step that determines rate is the removal of leaving group from the substrate haloalkane and generates a carbocation. Since the rate is only governed by substrate alone and no other nucleophile or solvent it is termed as unimolecuar substitution. The final step is attack of nucleophile on carbocation generated and formation of racemic products.

Answer 6

Chapter 7.4, Problem 7.7TIY

Interpretation Introduction

Interpretation: The major substitution product that would result from reaction of 2-bromo-2-methylpropane with concentrated aqueous ammonia should be predicted.

Concept introduction: Tertiary Haloalkane is a typical example for unimolecuar substitution. It proceeds via two-step mechanism. The first slow step that determines rate is the removal of leaving group from the substrate haloalkane and generates a carbocation. Since the rate is only governed by substrate alone and no other nucleophile or solvent it is termed as unimolecuar substitution. The final step is attack of nucleophile on carbocation generated and formation of racemic products.

Answer 7

Chapter 7.4, Problem 7.7TIY

Interpretation Introduction

Interpretation: The major substitution product that would result from reaction of 2-bromo-2-methylpropane with concentrated aqueous ammonia should be predicted.

Concept introduction: Tertiary Haloalkane is a typical example for unimolecuar substitution. It proceeds via two-step mechanism. The first slow step that determines rate is the removal of leaving group from the substrate haloalkane and generates a carbocation. Since the rate is only governed by substrate alone and no other nucleophile or solvent it is termed as unimolecuar substitution. The final step is attack of nucleophile on carbocation generated and formation of racemic products.

Answer 8

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Answer 11

Ch. 7.1 - Prob. 7.1E Ch. 7.2 - Prob. 7.2E Ch. 7.3 - Prob. 7.3E Ch. 7.3 - Prob. 7.5TIY Ch. 7.4 - Prob. 7.7TIY Ch. 7.5 - Prob. 7.9TIY Ch. 7.6 - Prob. 7.10E Ch. 7.7 - Prob. 7.11E Ch. 7.7 - Prob. 7.12E Ch. 7.7 - Prob. 7.13E

Solution Summary: The author explains that the major substitution product that would result from reaction of 2-bromo-2-methylpropane with concentrated aqueous ammonia is predicted.

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