Chapter 7, Problem 48P

(a)

Interpretation Introduction

Interpretation: The products formed due to elimination and most likely mechanism for below reactionsshouldbe written.

  

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two step unimolecuar elimination, abbreviated as $\text{E1}$ .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or $\text{E1}$ .

(b)

Interpretation Introduction

Interpretation: The rates of below three reactions should be compared.

  

Concept introduction: Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene.

If the leaving group present eliminates along with a proton in absence of any strong nucleophile the double bond formation might occur. Such reactions are known as two step unimolecuar elimination, abbreviated as $\text{E1}$ .If the still higher concentration is employed, reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or $\text{E1}$ .